Electromagnet investigation lab assignment

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Homework Help Overview

The discussion revolves around an investigation involving an alpha particle moving through a uniform magnetic field. The problem includes calculating the force on the particle, its acceleration, and the radius of its path within the magnetic field.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the necessary charge of the alpha particle to apply the force equation F = QvB. Questions arise regarding the charge value and its implications for calculations.

Discussion Status

Participants are exploring the relationship between the magnetic force and centripetal force, with some suggesting relevant equations for finding the radius of curvature. There is an ongoing exchange of ideas about the properties of the alpha particle and how they relate to the problem.

Contextual Notes

There is a noted uncertainty regarding the charge of the alpha particle and its role in the calculations, as well as the need for clarity on the direction of the force involved.

helpme2011
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Homework Statement



An alpha particle enters a uniform verical magnetic field of 1.0 T with a velocity of 2.0m/s East.
a) Find the force exerted on the particle by the field.
b) Find the acceleration of the particle.
c) Find the radius of curvature of the path of the particle.

Homework Equations



F= QvB ?

The Attempt at a Solution


B= 1.0 T
v= 2.0m/s
How do I solve it without given Q?
 
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What do you know about an alpha particle ?
 
Oh..I just googled it :S but does it have a charge of 3.2 x 10^-19 Coulombs? so would that just be my Q and plug that into the equation of F= QvB?
 
Yes, an alpha particle is composed of two protons and two neutrons. The charge of a proton is 1.6*10-19 Coulombs .

Force is a vector quantity, so presumably it should also have a direction associated with it.
 
Ok. Thanks! :)
and to find the radius, do i use the equation: a= v^2/r ?
 
To find radius ... the magnetic force will act as centripetal force (mv2/r)...
 
helpme2011 said:
Ok. Thanks! :)
and to find the radius, do i use the equation: a= v^2/r ?
Yes. That should work. Also, cupid's idea is equally good.
 
SammyS said:
Also, cupid's idea is equally good.
:biggrin: :biggrin: :biggrin: :biggrin:
 

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