Electromagnetic Induction and a coil of wire

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SUMMARY

The discussion focuses on calculating the electromotive force (emf) induced in a coil of wire with a diameter of 9.2 cm when the magnetic field decreases from 6.4 T to 6.1 T over 0.076 seconds. The formula used for emf is emf = -N delta phi/delta t, where phi represents the magnetic flux. The participants clarify that the magnetic field is perpendicular to the coil's area, and the angle theta is the angle between the normal of the area and the magnetic field, which is critical for accurate calculations.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for magnetic flux (phi = BAcos(theta))
  • Knowledge of the concept of electromotive force (emf)
  • Basic understanding of coil geometry and turns (N)
NEXT STEPS
  • Calculate the induced emf using the provided parameters and formulas
  • Explore the impact of the number of turns (N) in the coil on the induced emf
  • Study the relationship between magnetic field strength and induced emf in different coil configurations
  • Learn about Faraday's Law of Electromagnetic Induction in detail
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone interested in understanding electromagnetic induction and its applications in coil systems.

calculator20
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The magnetic field that is oriented perpendicularly through a 9.2 cm diameter coil of wire drops from 6.4 T to 6.1 T in 0.076 seconds. What is the emf induced in the coil?

Trying to answer this. My question is, if they are perpendicular then does that mean that cos90 makes phi = BAcos theta become zero therefore making the emf zero when put into emf = -N delta phi/delta t ? That doesn't seem right?
 
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calculator20 said:
The magnetic field that is oriented perpendicularly through a 9.2 cm diameter coil of wire drops from 6.4 T to 6.1 T in 0.076 seconds. What is the emf induced in the coil?

Trying to answer this. My question is, if they are perpendicular then does that mean that cos90 makes phi = BAcos theta become zero therefore making the emf zero when put into emf = -N delta phi/delta t ? That doesn't seem right?
The magnetic field is perpendicular to A, the cross section of the coil. Theta means the angle between the normal of A and the magnetic field.
 
calculator20 said:
The magnetic field that is oriented perpendicularly through a 9.2 cm diameter coil of wire drops from 6.4 T to 6.1 T in 0.076 seconds. What is the emf induced in the coil?

Trying to answer this. My question is, if they are perpendicular then does that mean that cos90 makes phi = BAcos theta become zero therefore making the emf zero when put into emf = -N delta phi/delta t ? That doesn't seem right?
How many turns in the coil?
 

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