Electromagnetic induction graph of E versus I

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SUMMARY

The discussion centers on the application of electromagnetic induction, specifically the relationship defined by the equation E = -L dI/dt. The user seeks clarification on how to derive the answer 'C' from this equation. A critical point raised is the distinction between the current 'I' in the larger coil versus the smaller rectangular coil, emphasizing that 'I' can be varied while assuming dI/dt equals zero. This indicates a need for a deeper understanding of the variables involved in the equation.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the equation E = -L dI/dt
  • Knowledge of inductance (L) and its role in circuits
  • Basic concepts of current (I) in electrical circuits
NEXT STEPS
  • Study the implications of varying current in inductive circuits
  • Explore the concept of inductance and its calculation
  • Learn about the behavior of coils in electromagnetic fields
  • Investigate the effects of dI/dt on induced electromotive force (EMF)
USEFUL FOR

Students in physics or electrical engineering, educators teaching electromagnetic theory, and anyone seeking to understand the principles of electromagnetic induction and its applications in circuit design.

delsoo
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Homework Statement



for this question, i only know that E=-L dI/dt... the ans is C , can anyone explain how to get C?

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The Attempt at a Solution

 

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Your "I only know" expression does not apply. I is in the big coil, not in the little rectangular one.

"Carrying a variable I" here means they are able to set the current to a number of values. (*) You may assume dI/dt = 0.

(*) So what do they vary in this way ? Aha!
 

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