- #1
PhysixChick
- 20
- 3
Homework Statement
A small circular metal ring of radius r is concentric with a large circular metal ring of radius 10r. Current in the outer ring flows counterclockwise due to an unpictured power supply. By adjusting the power supply, you can adjust I, the current in the large ring. The graph below shows I(t). Notice that I increases linearly from I0 to 2I0 from time t = 0 to time t = T
a. Sketch a rough, qualitative graph of the current in the small ring as a function of time. On your graph, let 'positive' current correspond to current flowing CW in the ring.
b.The small ring is made of a copper wire of cross-sectional area a. What is the resistance of the small ring? Let ρ Cube the resistivity of copper. Call your answer R.
c. Using the Biot-Savart rule, find the magnetic field, B (magnitude and direction) due to the large ring at the center of the small ring when the current in the large ring is 1.5I0. The direction can be described by words such as “into the page” or “out of the page.”
d. When the current in the large ring is 1.5I0, what is the current in the small ring? Neglect the small ring’s self-inductance. Answer in terms of R, r, I0, T, and any universal constants. The B field can be taken as uniform over the small ring.
Homework Equations
ρL/A = R
∫ B ⋅ ds = μ0I
and not too sure which other ones I would use.
The Attempt at a Solution
So I attempted a, b, and c.
For:
A. I understand that from 0 - T and from T on, it will be zero because the flux isn't changing (current is constant) and , it will be -I0 in between the T interval.
B. I got ρ(2πr)/a = R
C. I don't know if this is right, but I came up with B = μ0Ilarge/(2πr+2π(10r)) - μ0Ismall/(2πr)
D. For this part, I'm not too sure how to approach this.