A 20cm x 20cm square loop of wire lies in the xy-plane with its bottom edge on the x-axis. The resistance of the loop is 0.50[tex]\Omega[/tex]. A uniform magnetic field parallell to the z-axis is given by B=0.80y[tex]^{2}[/tex]t, where B is in tesla, y in meters, and t in seconds. What is the size of the induced current in the loop at t = 0.50s?(adsbygoogle = window.adsbygoogle || []).push({});

Induciton of Solonoid = ((magnetic constant)N^2A)/I

[tex]\epsilon[/tex] = d[tex]\phi[/tex]/dt

[tex]\phi[/tex] = magnetic flux

i thought first i would need to differentiate the original equation to find the emf of the loop and hence the current.

but thats where i got stuck? where does the y value come in?

once ive got the current i can find the induced current but am struggling with how to get the emf of the loop!

help would be appreciated!

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# ElectroMagnetic Induction - HELP!

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