Electromagnetic Levitation for a stationary hoverboard - How can I do it?

AI Thread Summary
A university student is developing a stationary hoverboard prototype that needs to support about 1kg with a desired lift of 100mm. Initial tests with electromagnets provided strong attraction but limited repulsion, achieving only 4mm lift, while Neodymium magnets offered better results with 70mm lift. The student seeks to control the hoverboard's movement using an Arduino but is unsure how to vary the magnetism effectively. Discussions highlight the rapid decrease of magnetic force with distance and suggest exploring mechanical systems to block or weaken magnetic forces for stability. A quadcopter-like design is proposed to help distribute forces and enhance control.
Ben Pickard
Messages
1
Reaction score
0
I am University Student currently working on a project to make a stationary hover board. This is just a prototype and does not need to support a human and only needs to support about 1kg but with as much "lift" or distance between the magnets as possible - (100mm?)

Ideally we want to be able to control the hover board by varying the magnetism of each magnet and so initially we have tested electromagnets (http://www.ebay.co.uk/itm/12V-DC-Sucked-Type-Electric-Lift-Lifting-Holding-Magnet-Electromagnet-Solenoid-/152038250371?var=&hash=item23662f9783:m:m8e-RjEY1odRj8cJupM1ymg) and although the attraction force was very strong they did not repel well at all- about 4mm.

We then tried 25x25mm Neodymium magnets with much better results (70mm lift) but we don't know how to vary or control the magnetism to control the hover board. We want to use an Arduino to make the board move on its own hence the initial thought of using electromagnets.

Any help would be much appreciated!
 
Physics news on Phys.org
Magnetic forces diminish rapidly with distance. Is there a specific reason want you can't achieve your goals with 4 mm lift?
 
anorlunda said:
Magnetic forces diminish rapidly with distance. Is there a specific reason want you can't achieve your goals with 4 mm lift?
Edit: welcome to physics forums
 
david280 said:
Most teens and kids are interested to ride on the hoverboard.
That so-called Hoverboard appears to have wheels. So much for hovering!
 
I think I understand the problem, and you don't have an easy solution. Magnetism loses its strength rapidly as you move away from it, and if you add the two poles of the magnet constantly wanting to flip your board over then you have a tough road ahead.

You might not need to use electromagnets though. If memory serves, there are a few materials that block/weaken magnetic force. If you get powerful enough magnets to give you the lift separation you want, then a mechanical system to block a small number of the magnets on one side or another might give you what you need.

I'm thinking that for stability you should use a shape like a quadcopter to spread out the forces and prevent flipping. Then use a shutter system to block some of the magnetism on one side. I don't think you would be able to turn using this system, but it should give you 2 axis movement.
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top