Electromagnetic Waves and Induction

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Homework Help Overview

The discussion revolves around calculating the magnetic flux through a loop that is positioned both perpendicular and tilted at an angle relative to a solenoid. The problem involves understanding the relationship between the solenoid's magnetic field and the loop's area, as well as applying the magnetic flux formula.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the magnetic flux formula, questioning how to incorporate the dimensions of both the solenoid and the loop. Some express confusion about the interaction between the solenoid's magnetic field and the loop.

Discussion Status

There is an ongoing exploration of the calculations for magnetic flux, with participants attempting to clarify their understanding of the formula and the parameters involved. Some have provided calculations but express uncertainty about their correctness, while others are questioning the assumptions made in their approaches.

Contextual Notes

Participants note the need to express answers using significant figures and are grappling with the implications of the loop's orientation on the magnetic flux calculation. There is mention of a potential discrepancy between their calculations and the expected answers from a textbook.

jlmessick88
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Homework Statement



The 2.0-cm-diameter solenoid in the figure passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.20 T.
What is the magnetic flux through the loop when it is perpendicular to the solenoid?
Φ1 = Wb

What is the magnetic flux through the loop when it is tilted at a 60 angle?
Φ2 = Wb

http://i63.photobucket.com/albums/h148/jlmessick88/jfk_Figure_25_P08.jpg

Homework Equations



Φ = AB cos()

The Attempt at a Solution


? No idea :(

Thanks
 
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You have the equation for calculating Φ. You have B. You have A. You have θ. What seems to be the trouble?
 
getting confused with what i should be doing with the solenoid and the loop...wouldn't one effect the other or am i supposed to be using both diameters
 
The question asks what the magnetic flux through the loop is. The loop does not have a magnetic field, so how could it affect the solenoid?
 
oh! ok that makes sense...
but for when it's tilted 60 degrees... it would be .01^2 * pi = 3.14*10^-4 *.2T = 6.28*10^-5 * cos(60) = 3.14 * 10^-5...but that's not the correct answer...i don't understand why...
 
The question asks what the magnetic flux through the loop is. The loop does not have a magnetic field, so how could it affect the solenoid?

EDIT:

cepheid said:
The question asks what the magnetic flux through the loop is.
 
What is the magnetic flux through the loop when it is perpendicular to the solenoid?
Express your answer using two significant figures.
=6.3×10−5
Correct
.01^2 * pi = 3.14*10^-4
3.14*10^-4 *.2 = 6.28*10^-5
6.28*10^-5 * cos(0) = 6.28*10^-5

so for the second part wouldn't i just use cos(60)??
 
jlmessick88 said:
What is the magnetic flux through the loop when it is perpendicular to the solenoid?
Express your answer using two significant figures.
=6.3×10−5
Correct
.01^2 * pi = 3.14*10^-4
3.14*10^-4 *.2 = 6.28*10^-5
6.28*10^-5 * cos(0) = 6.28*10^-5

so for the second part wouldn't i just use cos(60)??

Yes, you just use flux=BAcos(60). I don't know why you're doing:

.01^2 * pi = 3.14*10^-4
3.14*10^-4 *.2 = 6.28*10^-5
6.28*10^-5 * cos(0) = 6.28*10^-5
 
but when i used BAcos(60), i get 3.14*10^-5, that's wrong...why??
 
  • #10
Not really seeing why the answer is wrong. What does your book say?
 
  • #11
i don't know what the answer is...it's just saying it's wrong...
 
  • #12
Its the same answer for both.. even though I'm sure this is too late now
 

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