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Electromagnetic Waves and Induction

  1. Jul 2, 2009 #1
    1. The problem statement, all variables and given/known data

    The 2.0-cm-diameter solenoid in the figure passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.20 T.
    What is the magnetic flux through the loop when it is perpendicular to the solenoid?
    Φ1 = Wb

    What is the magnetic flux through the loop when it is tilted at a 60 angle?
    Φ2 = Wb

    http://i63.photobucket.com/albums/h148/jlmessick88/jfk_Figure_25_P08.jpg
    2. Relevant equations

    Φ = AB cos()

    3. The attempt at a solution
    ???? No idea :(

    Thanks
     
  2. jcsd
  3. Jul 2, 2009 #2

    cepheid

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    You have the equation for calculating Φ. You have B. You have A. You have θ. What seems to be the trouble?
     
  4. Jul 2, 2009 #3
    getting confused with what i should be doing with the solenoid and the loop...wouldn't one effect the other or am i supposed to be using both diameters
     
  5. Jul 2, 2009 #4

    cepheid

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    The question asks what the magnetic flux through the loop is. The loop does not have a magnetic field, so how could it affect the solenoid?
     
  6. Jul 2, 2009 #5
    oh!!! ok that makes sense...
    but for when it's tilted 60 degrees... it would be .01^2 * pi = 3.14*10^-4 *.2T = 6.28*10^-5 * cos(60) = 3.14 * 10^-5...but that's not the correct answer...i don't understand why...
     
  7. Jul 2, 2009 #6

    cepheid

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    The question asks what the magnetic flux through the loop is. The loop does not have a magnetic field, so how could it affect the solenoid?

    EDIT:

     
  8. Jul 2, 2009 #7
    What is the magnetic flux through the loop when it is perpendicular to the solenoid?
    Express your answer using two significant figures.
    =6.3×10−5
    Correct
    .01^2 * pi = 3.14*10^-4
    3.14*10^-4 *.2 = 6.28*10^-5
    6.28*10^-5 * cos(0) = 6.28*10^-5

    so for the second part wouldn't i just use cos(60)??
     
  9. Jul 2, 2009 #8

    ideasrule

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    Yes, you just use flux=BAcos(60). I don't know why you're doing:

    .01^2 * pi = 3.14*10^-4
    3.14*10^-4 *.2 = 6.28*10^-5
    6.28*10^-5 * cos(0) = 6.28*10^-5
     
  10. Jul 3, 2009 #9
    but when i used BAcos(60), i get 3.14*10^-5, that's wrong...why?!?!
     
  11. Jul 3, 2009 #10
    Not really seeing why the answer is wrong. What does your book say?
     
  12. Jul 3, 2009 #11
    i don't know what the answer is...it's just saying it's wrong...
     
  13. Jul 9, 2009 #12
    Its the same answer for both.. even though i'm sure this is too late now
     
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