Electromagnetism, find magnitude and direction of the resulting force on wire.

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SUMMARY

The resulting force on a 25-meter length of a wire carrying a current of 70 amperes towards the east in a uniform magnetic field of 0.15 T directed north is calculated using the formula F = ILB sin θ. Substituting the values, F = 70 * 25 * 0.15 * sin 90 results in a force of 262.5 N directed towards the right (east). The direction of the force is confirmed to be perpendicular to both the current and the magnetic field using Fleming's left-hand rule.

PREREQUISITES
  • Understanding of electromagnetic principles
  • Familiarity with Fleming's left-hand rule
  • Knowledge of the formula for magnetic force on a current-carrying wire
  • Basic proficiency in vector analysis
NEXT STEPS
  • Study the applications of Fleming's left-hand rule in various electromagnetic scenarios
  • Explore the effects of varying magnetic field strengths on force calculations
  • Learn about the Lorentz force law and its implications in electromagnetism
  • Investigate the relationship between current, magnetic fields, and forces in different configurations
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Students of physics, electrical engineers, and anyone interested in understanding the principles of electromagnetism and their practical applications in current-carrying conductors.

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A long straight horizontal wire carries a current of 70 amperes towards the east. The wire is placed in a uniform magnetic field of intensity 0.15 T towards the north.

Find the magnitude and direction of the resulting force on a 25m length of this wire



F=ILB sin [tex]\theta[/tex]



F = 70*25*0.15sin 90

F = 262.5 N towards the right

Is it the right answer?
 
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The force should be perpendicular to east and north. Using Flemming's left hand rule find the direction.
 

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