kolleamm said:
One has wire with a 1mm diameter and the other has half that diameter 0.5mm. Assuming they both have the same mass of wire which would be stronger or better?
by "stronger" i assume you mean the field not the wire ?
Really it depends on how well your coil can dissipate heat.
Magnetic field strength you will find is in proportion to the
product of amps and turns.
So there's no obvious inherent advantage to either of your postulated configurations over the other.
The smaller wire has 1/4 the cross sectional area of the larger
so will have 4X the resistance per foot
and you should be able to fit 4X as many turns into the same volume .
Now let's look at some practical arithmetic...
IF
from a given mass of copper you can make L feet of wire with diameter 1mm
THEN
from same mass of wire you can make 4L feet of wire with diameter 0.5 mm
since Power = I
2R ;
IF
through wire of 1mm diameter you can pass current I and dissipate power P per foot
THEN
through wire of 0.5mm diameter you can pass current I/2 and still dissipate power P per foot
because I
2 X R = P = (I/2)
2 X 4R
Now since you can get 4X as many turns of smaller wire in the same space
and operate them at half the current with same P per foot
it would appear that your product of amps X turns will double
[(amps/2) X (turns X 4
) ] divided by [(amps ) X ( turns ) ] = 2
meaning you'd get twice the field strength with the smaller wire.
BUT the gotcha is -
you most likely can't operate them at the same P per foot
because the coil made from smaller wire has 4X as many feet
and at 4X as many ohms per foot the coil made of smaller wire will have total resistance 4 X 4 = 16X as many ohms.
and its power dissipation is limited by its surface area.
Taking this line of thought to the extreme
IF you are limited by power dissipation in the coil
THEN you'll have to use 1/4 as much current to keep power dissipation the same
because (I/4)
2 X (16R) = I
2R
and you'll have the same amp turns for both arrangements
because (I/4) X (turnsX4) = I X turns.
So there's no advantage in that case.
BUT -
IF
you're not limited by heat dissipation in the coil,
because perhaps your coil sees a small duty cycle so there is time for heat to conduct out between cycles
or it's a linear application that spends most of its time at low current
THEN
Yes there's an advantage to using the smaller wire in that you'll need less current to achieve a given field strength.
Just be sure you have enough voltage available in your power supply to push the requisite current through the ohms of your coil when it's at maximum expected temperature.
Make sense?
old jim