Electron Cloud described by a Gaussian distribution

Click For Summary
SUMMARY

The discussion focuses on calculating the change in electric field across an electron cloud described by a Gaussian distribution, consisting of 12 x 109 electrons, drifting between two plates with a potential difference of 15V. The tutor emphasized the necessity of applying Gauss' law, specifically the spherical form of the equation for electric flux, to derive the electric field. The correct approach involves using the surface area of a sphere and expressing the enclosed charge based on the Gaussian distribution. The initial attempt at a solution highlighted the misunderstanding of the appropriate geometry for the problem.

PREREQUISITES
  • Understanding of Gauss' law and its applications
  • Familiarity with Gaussian distributions in physics
  • Knowledge of electric fields and potential differences
  • Ability to perform calculations involving spherical symmetry
NEXT STEPS
  • Study the spherical form of Gauss' law for electric fields
  • Learn how to derive charge distributions from Gaussian functions
  • Explore the concept of electric flux and its applications in electrostatics
  • Practice problems involving electric fields in different geometries
USEFUL FOR

Physics students, electrical engineers, and anyone studying electrostatics or Gaussian distributions in electric fields will benefit from this discussion.

MrBeano
Messages
1
Reaction score
0

Homework Statement



A cloud of electrons are drifting from a negative plate to a positive plate after being liberated by a laser pulse, (separated by a distance z = 10cm with an original potential difference of 15V) at an instant in time the centre of the cloud has traveled 25mm from the negative plate and the spatial distribution of the charge is described by a Gaussian distribution with a standard deviation of 1.0mm.

Calculate the the change in electric field across the electron cloud if the electron cloud consists of 12 X 109 electrons.

Homework Equations



The tutor said that Gauss' law, in one form or another must be used in the solution.

After some further reading I discovered the equation for the cylindrical gaussian surface of;

Flux = \oint E dA

= E \oint da

= E * 2\pirh

Flux also equals q/\epsilon

Therefore

E = s / 2\pi\epsilonr

The Attempt at a Solution



I have not really found a reasonable numerical solution yet, which has led me to believe that the problem lies with my derivation of E or my understanding of what E means in the context of the question.
 
Physics news on Phys.org
To make this approach work you need to do two things. 1) The cylindrical form you quoted is inappropriate to the problem, which has spherical symmetry. Use the spherical form instead (hint: it involves the surface area of a sphere.) 2) Express the portion q(r) of total charge that is enclosed within the sphere of radius r by using the given charge distribution.
 

Similar threads

Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
13
Views
8K
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 22 ·
Replies
22
Views
7K
  • · Replies 8 ·
Replies
8
Views
9K
  • · Replies 7 ·
Replies
7
Views
6K