Electron flow through a wire time

Click For Summary

Homework Help Overview

The discussion revolves around calculating the time it takes for 1 mole of electrons to flow through a gold wire, given the electron drift speed and wire dimensions. The subject area includes concepts from electricity and chemistry, particularly relating to current and charge flow.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between current, charge, and the number of electrons, questioning how to convert the calculated current into a mole-based measurement. There is discussion about the definitions of current and charge per time, as well as the conversion of electron flow rates.

Discussion Status

The discussion is ongoing, with participants providing insights into the definitions of current and charge, as well as attempting to clarify the original problem's requirements. Some participants express confusion about the calculations and the transition from electron current to moles per day, indicating a lack of consensus on the approach.

Contextual Notes

There are indications of missing chemistry background for some participants, which may affect their understanding of mole conversions. Additionally, there is uncertainty regarding the interpretation of the original question and the expected format of the answer.

fsm
Messages
88
Reaction score
0

Homework Statement


The electron drift speed in a 1.00 -mm-diameter gold wire is 5.50*10^-5 m/s
How long does it take 1 mole of electrons to flow through a cross section of the wire?

Homework Equations


I=n*q*V*A

The Attempt at a Solution


I=(5.9*10^28)*(1.6*10^-19)*(3*10^-5)*(.0005^2*pi)
I=0.222 col/sec

I believe my answer is correct. The problem is I never had chem so I don't know how to convert to a mole. Any help?
 
Physics news on Phys.org
I'll answer the mole part: 1 mole of electrons would be 6.022x10^23 electrons. What's a "col/sec"?
 
It's a couple of things. Its a rate the charge moves through a wire. Isn't this also the electron current? Or I can convert it to the electron current?
 
An amp is charge/time. What unit is amps or charge per time in? Har har:biggrin:
 
Ah, coloumbs/sec. I usually see that as C/s. Didn't recognize what you were getting at there.
 
Guess I'm not getting it. So do I convert my answer to electron current and then divide by 6.022x10^23?
 
I'm not sure what you mean by convert to electron current. To me, that's what you already have. Think of the definition of current (charge/time). Start with: How many coloumbs would be in one mole of electrons?

By the way looking at your first calculation I=(5.9*10^28)*(1.6*10^-19)*(3*10^-5)*(.0005^2*pi)
Isn't the drift speed 5.50x10^-5 m/s?
 
I used the example my teacher provided I just transposed some numbers. I see now he used what he called the formal definition I=n*A*V_d*q. Then he made a conversion to -e/sec by dividing 1.6*10^-19. Which cancels out the charge. Seeing this I now understand he was just using the formula i=n*A*V_d where little i is the electron current. Recalculating I get about 2.55*10^18 -e/sec. The answer is wanted in a day. Do I first convert to -e per day then I divide by 6.02*10^23?
 
Last edited:
If the point of the question is to get the number of moles per day, then I would think your reasoning is correct. But I don't understand how it got to this from the original question you posted, which to me is asking something different. So I'm not sure what to say about that.
 
  • #10
This problem is a bugger. I'm still getting the wrong answer. I know its me and can't figure it out. I even tried to do the same type of problem in my book and got that wrong too. Please any help.
 
  • #11
I'm not sure what you're trying to accomplish anymore, is it still the question in your original post? I don't understand where this e- per day thing is coming from. Perhaps if you post your entire calculation, we can see if you are making some kind of math error. What is the right answer supposed to be?
 

Similar threads

Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
11K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 31 ·
2
Replies
31
Views
8K
Replies
4
Views
14K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K