- #1

victorializ

- 20

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## Homework Statement

The resistivity of gold is 2.44 x 10-8 Ω m at a temperature of 20°C. A gold wire, 0.5 mm in diameter and 44 cm long, carries a current of 380 ma. The number of electrons per second passing a given cross section of the wire, is closest to:

A) 2.4 × 10^18

B) 1.2 × 10^22

C) 2.8 × 10^14

D) 2.4 × 10^17

E) 6.3 × 10^15

## Homework Equations

R=ρL/A

## The Attempt at a Solution

R=(2.44 x 10^-8) (.44)/∏(.00025^2)

R= .0547

then i multiplied the resistance by the current (.38) to get .021 for a voltage.

then i divided that by (1.6 x 10^-19) and got 1.3 x 10^17 which isn't right but is close to the answer which is A