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Electron in a uniform field, acceleration

  1. Feb 12, 2009 #1
    1. The problem statement, all variables and given/known data

    An electron has an initial velocity of 2.5 ×
    106 m/s in the x direction. It enters a uniform
    electric field ~E = (320 N/C) ˆj which is in the
    y direction.
    The charge and mass of an electron are
    1.6×10−19 C and 9.11×10−31 kg, respectively.
    Find the acceleration of the electron. An-
    swer in units of m/s2.

    2. Relevant equations

    MA=QE
    a=QE/m



    3. The attempt at a solution

    320*(1.6e-19)/(9.11e-31)= 5.62019759e13
    Attempted to insert exactly as shown and was marked wrong. I can't seem to find a reason why the answer to this is wrong and I've hit a bit of roadblock so to speak

    Any help is appreciated
     
  2. jcsd
  3. Feb 12, 2009 #2
    I'm not exactly sure but could the fact that the Electric field is going in the y direction while the electron is moving in the x direction?
     
  4. Feb 12, 2009 #3

    Delphi51

    User Avatar
    Homework Helper

    Your answer looks good to me.
    The acceleration will be upward - have you a way to indicate the direction in your entry?
    Also, you have used 3-digit accuracy in e, m and E so your final answer should be rounded to 3 digits.
     
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