# Electron in a uniform field, acceleration

## Homework Statement

An electron has an initial velocity of 2.5 ×
106 m/s in the x direction. It enters a uniform
electric field ~E = (320 N/C) ˆj which is in the
y direction.
The charge and mass of an electron are
1.6×10−19 C and 9.11×10−31 kg, respectively.
Find the acceleration of the electron. An-
swer in units of m/s2.

MA=QE
a=QE/m

## The Attempt at a Solution

320*(1.6e-19)/(9.11e-31)= 5.62019759e13
Attempted to insert exactly as shown and was marked wrong. I can't seem to find a reason why the answer to this is wrong and I've hit a bit of roadblock so to speak

Any help is appreciated

## Answers and Replies

I'm not exactly sure but could the fact that the Electric field is going in the y direction while the electron is moving in the x direction?

Delphi51
Homework Helper
Your answer looks good to me.
The acceleration will be upward - have you a way to indicate the direction in your entry?
Also, you have used 3-digit accuracy in e, m and E so your final answer should be rounded to 3 digits.