Electron scattering: nuclear radius to nucleon number relationship

  • Thread starter AlexCdeP
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  • #1
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Hi! I am extremely confused on what seems to be quite a simple question. The question contains a graph of root mean square radius <r[itex]^{2}[/itex]> plotted against A[itex]^{1/3}[/itex] where A is the nucleon number. In the lecture notes he specifies that <r[itex]^{2}[/itex]> is not the same as R but does not really say specifically what the difference is. It is given that the gradient of the line in this graph is 0.96. I am meant to find the value of R[itex]_{0}[/itex] in the relationship R=R[itex]_{0}[/itex]A[itex]^{1/3}[/itex] but I'm not certain how to find it because I dont know what the relationship between the rms r and R is.

Any help would be amazing.

I have worked through trying to use the charge radius but without success, he never mentioned the charge radius in the lecture so I'm not sure what to do. http://en.wikipedia.org/wiki/Charge_radius
 

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  • #2
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If you have a uniform sphere of radius R, what is the (squared) rms radius <r2> of its volume? Hint: You'll need an integral (or a formula).
 
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Thanks so much I think I'm on the right track now. So for a uniform sphere you use some spherical coordinate integrals to find that the rms radius is related to the radius by [itex]\frac{3}{5}[/itex]R[itex]^{2}[/itex]. Is this the correct formula to get?

Also am I right in saying that I am effectively finding the expectation value of r[itex]^{2}[/itex]?
 
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Finally got the answer! Thanks again man couldn't have done it without you!
 
  • #5
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Thanks so much I think I'm on the right track now. So for a uniform sphere you use some spherical coordinate integrals to find that the rms radius is related to the radius by [itex]\frac{3}{5}[/itex]R[itex]^{2}[/itex]. Is this the correct formula to get?

Also am I right in saying that I am effectively finding the expectation value of r[itex]^{2}[/itex]?
Yup.
 

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