Electron shot between plates (electric field)

Click For Summary
SUMMARY

The discussion revolves around solving a physics problem involving an electron shot between two charged plates in a uniform electric field of 2.00 x 103 N/C. The electron's initial velocity is 6.00 x 106 m/s at a 45-degree angle. Participants clarify that the force on the electron can be calculated using F = Eq, where q is the charge of the electron (-1.6 x 10-19 C). The solution involves breaking down the initial velocity into horizontal and vertical components and applying projectile motion equations to determine if the electron strikes one of the plates and the distance from the left edge.

PREREQUISITES
  • Understanding of electric fields and forces (F = Eq)
  • Knowledge of projectile motion principles
  • Ability to decompose vectors into components
  • Familiarity with the charge of an electron (-1.6 x 10-19 C)
NEXT STEPS
  • Study the relationship between electric fields and forces on charged particles
  • Learn how to resolve vectors into horizontal and vertical components
  • Review projectile motion equations and their applications
  • Explore the concept of uniform electric fields and their effects on charged particles
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and projectile motion, as well as educators seeking to clarify concepts related to electric fields and motion of charged particles.

miroku2192
Messages
3
Reaction score
0

Homework Statement



I've been staring at this last problem for a while now...but i really don't get it. So if someone could explain to me how to do this, that'd be great. Thanks:

In Fig. 22-64, a uniform upward electric field E of magnitude 2.00 x 10^3 N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 10.0 cm and separation d - 2.00 cm. An electron is then shot between the plates from the left edge of the lower plate. The initial velocity of V(sub zero) of the electron makes an angle theta =45.0 degrees with the lower plate and has a magnitude of 6.00 x 10^6 m/s.
(a) will the electron strike one of the plates? (b) If so, which plate and how far horizontally from the left edge will the electron strike?

I'm really confused on this...so if someone could help that'd be great. I was never really good at physics.

Homework Equations



Relevant equations? There were none provided..?

The Attempt at a Solution



Can someone just point me in the right direction first? I'm a bit confused on how I'm supposed to go about even TACKLING the problem. Would i use the E= kQ/r^2 ? Since it's only one electron being acted on by the electric field? So it's like a point electric field thing?
 
Physics news on Phys.org
miroku2192 said:
Would i use the E= kQ/r^2 ? Since it's only one electron being acted on by the electric field? So it's like a point electric field thing?
No, that's the field produced by a point charge. You already know the field. You must find the force that the given field exerts on the electron. (What's the relationship between F, E, and q?)
 
Doc Al said:
No, that's the field produced by a point charge. You already know the field. You must find the force that the given field exerts on the electron. (What's the relationship between F, E, and q?)

Ohh...i see, so it's like a mix of electricity + projectile motions right? Because... F= Eq, and E is given, and q i know because it's the same for both protons + electrons right? something like -1.6 x 10^-19? Anyway, after i find the force in Newtons, i can just set it up as F = mass x acceleration, figure out acceleration and use projectile motions stuff right? I'm a bit shakey on projectile motions stuff though...when it says "a magnitude of 6.00 x 10^6 m/s.", does that mean after i find out acceleration, the initial velocity value i use is 6.00 x 10^6 m/s ?
 
miroku2192 said:
Ohh...i see, so it's like a mix of electricity + projectile motions right? Because... F= Eq, and E is given, and q i know because it's the same for both protons + electrons right? something like -1.6 x 10^-19? Anyway, after i find the force in Newtons, i can just set it up as F = mass x acceleration, figure out acceleration and use projectile motions stuff right?
Exactly right.
I'm a bit shakey on projectile motions stuff though...when it says "a magnitude of 6.00 x 10^6 m/s.", does that mean after i find out acceleration, the initial velocity value i use is 6.00 x 10^6 m/s ?
Yes, but realize that the initial velocity is at an angle, so you need to find horizontal and vertical components. Only the vertical component of motion is accelerated--just like with regular projectile motion.
 
Doc Al said:
Exactly right.

Yes, but realize that the initial velocity is at an angle, so you need to find horizontal and vertical components. Only the vertical component of motion is accelerated--just like with regular projectile motion.

Oh right...i have to split up the x components and y components...Thanks so much, i think i get this question now. I really appreciate ALL your help!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 58 ·
2
Replies
58
Views
6K
Replies
4
Views
3K
  • · Replies 16 ·
Replies
16
Views
1K
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 26 ·
Replies
26
Views
3K
Replies
19
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K