Electrostatic Field and Particle Motion: Homework Solution and Explanation

Click For Summary
SUMMARY

The discussion centers on the analysis of electric fields produced by two identical positively charged spheres, each carrying a charge of +q C. It confirms that the electric field along line LM is zero due to the repulsive forces between the charges, while the field along line AB also remains absent as it lies between the two charges. The motion of a positively charged particle initially at rest near one of the charges is characterized by a decrease in potential energy as it moves away, leading to an increase in velocity and a decrease in acceleration due to the diminishing force between the charges. Key equations such as P.E = K.E and a = F/M are essential for understanding the dynamics involved.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with Coulomb's Law and its application
  • Knowledge of Newton's laws of motion
  • Basic concepts of potential energy and kinetic energy
NEXT STEPS
  • Study Coulomb's Law and its implications for electric field calculations
  • Learn about the superposition principle in electric fields
  • Explore the relationship between electric potential energy and kinetic energy in charged particle motion
  • Investigate the concept of electric field lines and their representation
USEFUL FOR

Students studying physics, particularly those focusing on electrostatics and particle dynamics, as well as educators seeking to clarify concepts related to electric fields and forces.

BoanviaFx
Messages
30
Reaction score
0

Homework Statement


Can someone confirm if I answered correctly?

Question: Two small identical spheres each carrying a charge, +q C, are placed on the line LM as shown in the diagram:
v2tg8x.jpg

Describe how the intensity and direction of the electric field produced by the two charges varies:
i) Along the line LM, and
ii) Along the line AB

b) Describe how the acceleration and velocity of a positively charged particle initially at rest on the line LM very close to one of the charges +q, changes as the particle moves away from the charge.

Homework Equations

The Attempt at a Solution


i) Since the charges are both positive there will be a repulsion and the electric field along LM will be vacant.
ii) As for the direction same applies since both of the fields collide, no fields will be present along line AB since it is positioned between the two spheres.

b) The velocity would change due to a decrease in potential energy, as the other charge moves away the distance r begins to increase. When r=infinity the potential energy would be equal to zero. P.E=K.E

As for the acceleration, since the mass is a constant the force between the two charges would decrease.
a=F/M
 
Physics news on Phys.org
BoanviaFx said:
i) Since the charges are both positive there will be a repulsion and the electric field along LM will be vacant.
Vacant meaning zero ? No.

ii) As for the direction same applies since both of the fields collide, no fields will be present along line AB since it is positioned between the two spheres.
Again. No. Both fields will be present. The term "collide" isn't applicable to fields in this stage of your education. The fields are static.

b) The velocity would change due to a decrease in potential energy, as the other charge moves away the distance r begins to increase. When r=infinity the potential energy would be equal to zero. P.E=K.E
It says "Initially at rest". With "other charge" you mean the particle ? With "distance r" you mean what, exactly ? Do you realize X is also on the line LM ?

As for the acceleration, since the mass is a constant the force between the two charges would decrease.
a=F/M
Which two charges, exactly ? There are three of them in this story...PS the section 2. Relevant eqations is blank on my screen. But you do need equations for the filed. make sure they are correct and complete when you post them.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
23
Views
5K
Replies
1
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K