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Electrostatic FieldSchey's Notation

  1. Nov 16, 2009 #1
    Hey there,

    I am just seeking some clarification wrt the notation that I have come across for the Electrostatic Field:

    [tex]\mathvf{E}(\mathbf{r})=\frac{1}{4\pi\epsilon_0}\int\int\int_V\frac{\rho(\mathbf{r'})\hat{\mathbf{u}}(\mathbf{r'})}{|\mathbf{r}-\mathbf{r'}|^2}\,dV'[/tex]

    So are all of the 'primes' just saying that the [itex]\rho,\hat{u}, dV[/itex] are simply those that correspond to the same location?

    It seems like it is just a 'shorthand' notation to avoid a bunch of subscripts.

    Is this correct?

    Thanks,
    Casey
     
  2. jcsd
  3. Nov 17, 2009 #2

    physicsworks

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    Gold Member

    All the "primes" are correspond to the source [tex]dq[/tex] of your (continuous) charge distribution, when [tex]\mathbf{r}[/tex] corresponds to the filed point, i.e. the point, where you want to find [tex]\mathbf{E}[/tex].
    [tex]|\mathbf{r}-\mathbf{r'}|[/tex] is simply the distance between the source [tex]dq[/tex] and the field point [tex]\mathbf{r}[/tex].
     
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