Electrostatic Force: -0.7nC Charge at Origin

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Homework Help Overview

The problem involves calculating the electrostatic force on a -0.7nC charge located at the origin due to two other charges positioned at specified distances along the x and y axes. The task includes finding both the magnitude of the force and the angle it makes with the positive x-direction.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of Coulomb's law to determine the forces exerted by the other charges on the charge at the origin. There is mention of calculating forces along the x and y axes and uncertainty about the next steps after obtaining these values. Questions arise regarding the process of vector addition of the forces.

Discussion Status

Some guidance has been provided regarding the addition of forces as vectors, with suggestions to use either a vector triangle or component addition. Participants are exploring the implications of these methods but have not reached a consensus on the approach to take next.

Contextual Notes

Participants are working within the constraints of the problem statement and the requirement to express the final answers in specific units and formats. There is an ongoing discussion about the clarity of vector addition in this context.

peaceandlove
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Homework Statement


A -0.7nC charge is located at the origin, while a 1.9nC charge is located 3.9 m away along the x-axis and a 0.8nC charge is located -1.7m away along the y-axis. The Coulomb constant is 8.98755*10^9 Nm^2/C^2. Find the magnitude of the electrostatic force on the charge at the origin. Answer in units of nN.
What is the angle between the electrostatic force on the charge at the origin and the positive x-direction? Answer in degrees as an angle between -180 and 180 measured from the positive x-axis, with counterclockwise positive. Answer in units of degrees.

Homework Equations


F=k(Q/r^2)


The Attempt at a Solution


I used the equation F=k(Q/r^2) to find the force of the charge between the origin and each of the charges. For the force along the y-axis, I got 2.960604706e-9 and -3.064984998 along the x-axis. However, I'm not sure where to go from there.
 
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Hi peaceandlove! :smile:

(try using the X2 tag just above the Reply box :wink:)
peaceandlove said:
I used the equation F=k(Q/r^2) to find the force of the charge between the origin and each of the charges. For the force along the y-axis, I got 2.960604706e-9 and -3.064984998 along the x-axis. However, I'm not sure where to go from there.

You have two forces, so now all you have to do is add them.

Forces are vectors, so you use the vector law of addition …

in other words, you can add them by using a vector triangle, or you can just add the components (same result) …

since the two forces in this case are perpendicular, either method should be extremely easy. :wink:
 
What do you mean by add the component?
 
peaceandlove said:
What do you mean by add the component?

(just got up … :zzz:)

If F has components Fx and Fy, and G has components Gx and Gy, then vector addition means you add the components:

if H = F + G, then H has components Fx + Gx and Fy + Gy :smile:
 

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