Electrostatic force on a parallel plate

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Homework Help Overview

The discussion revolves around calculating the electrostatic force between parallel plates in a capacitor. Participants are exploring the relationship between charge, electric field, and force, questioning the assumptions and formulas typically used in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the formula for force, questioning why it may not simply be F=qE. There are suggestions to consider alternative methods, such as Coulomb's law or the electric field due to a sheet of charge. Some express confusion regarding the electric field's value and its implications for the force calculation.

Discussion Status

The discussion is active, with participants raising questions about the direction of forces and the correct calculation of the electric field. There is a recognition of potential misunderstandings regarding coefficients in the equations, and some participants are encouraged to calculate the electric field to clarify their reasoning.

Contextual Notes

Participants appear to be grappling with the nuances of electrostatics, particularly in the context of capacitors, and there may be assumptions about the electric field that are being questioned. The original poster's task is framed within a homework context, which may impose certain constraints on the discussion.

serverxeon
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I'm tasked to find the force one parallel plate exert on the other plate in a capacitor.

somehow the force isn't just F=qE, where E=Q/2εA

What am I missing here?
 
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What am I missing here?
Erm - direction?

You can check by using another method ... i.e. Coulombs law for a point charge and add them up, or start with the electric field due to a sheet of charge by itself.
 
i mean, my solution is lacking so coefficient.
based on my (confused and vague) understanding, the electric field is actually 1/2 E or something?
 
Is it? Why not calculate the field?
 

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