Electrostatic Potential Energy of a Conducting Sphere

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SUMMARY

The total electrostatic potential energy (U) of a conducting sphere with radius r0 and total charge Q is derived from the work done to charge the sphere. The correct formula is U = (1/(4πε0)) * (Q2/r0), where ε0 is the permittivity of free space. The work done to move a charge dq from infinity to the sphere's surface is calculated using the integral of dW = kq * dq/r0, leading to the final expression for potential energy. The discussion also touches on how to adapt the formula if charge density (ρ) is introduced instead of total charge (Q).

PREREQUISITES
  • Understanding of electrostatics and Coulomb's law
  • Familiarity with the concept of electric potential
  • Knowledge of integration techniques in calculus
  • Basic concepts of charge distribution on conductors
NEXT STEPS
  • Study the derivation of electric potential energy for different charge distributions
  • Learn about the implications of charge density (ρ) on electrostatic calculations
  • Explore the relationship between electric field and potential energy in electrostatics
  • Investigate the role of permittivity (ε0) in electrostatic equations
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Students studying electrostatics, physics educators, and anyone interested in understanding the principles of electric potential energy in conducting spheres.

George3
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Homework Statement


Determine the total electrostatic potential energy of a conducting sphere of radius r_0 that carries a total charge Q distributed uniformly on its surface. Give your answer in terms of Q, r_0, epsilon_0 and appropriate constants.


Homework Equations





The Attempt at a Solution



I know that U = QV and I know that V = kQ/r. I tried to answer it as U = (1/(4pi*epsilon_0))*Q^2/r_0 but that seems to be incorrect. Can anyone point me in the right direction?
 
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The electrostatic potential energy of the sphere is equal to the work done while it is charged.
If there is q charge on the sphere, the potential is kq/r0 on it surface. The work needed to move a charge dq from infinity to the surface of the sphere is:

<br /> <br /> dW=kq*dq/r_0

To get the whole work, you have to integrate from q=0 to q=Q.

ehild
 
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So if you integrate dW = kq *dq/r you end up getting W = k/r * the integral of q *dq from 0 to Q. Which just ends up being W = kQ^2/2r right?
 
George3 said:
So if you integrate dW = kq *dq/r you end up getting W = k/r * the integral of q *dq from 0 to Q. Which just ends up being W = kQ^2/2r right?

Yes, but with r0, the radius of the sphere.

ehild
 
i have a question similar to this. I was wondering if the question was rephrased to say that the sphere has a charge density, p, instead of a charge q how you would answer it?

Would simply become a Q/(volume of sphere) instead of q in your integral equation with everything else remaining the same?

Ps. sorry if this is not the correct format to ask a question (im new on the forum). If you guys want me to make a new thread please let me know thanks!
 

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