- #1

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## Homework Statement

(y+2)dx +y(x+4)dy=0

## Homework Equations

## The Attempt at a Solution

∫(1/x+4)dx + ∫(y/y+2)dy=0

ln(x+4)-2ln(y+2)+y=lnc

Here is where I get confused how do I make this into an explicit solution,

that +y really bothers me.

I was thinking ln [ (x+4)/(y+2)^2] +y = lnc

raising both sides to e^x

(x+4)/(y+2)^2+e^y=c

but the answer is

x+4 = [(y+2)^2]*e^(-y+1)