How do I modify plane waves to represent the EM field of a lightbulb?

e101101
Messages
10
Reaction score
0
Homework Statement
Part c
Relevant Equations
B=Bocos(k•r±⍵t)
E=Eocos(k•r±⍵t)
Irradiance=P/A
I don't know where to start for part (c), I've managed to get (a) and (b).
Can someone simply guide me, I think I'm having trouble understanding what the teacher means by just having an x dependance...
Does this mean I only work with the x components of the magnetic field and the electric field? What about the direction fo propagation?
 

Attachments

  • Screen Shot 2019-09-19 at 12.09.44 PM.png
    Screen Shot 2019-09-19 at 12.09.44 PM.png
    81.5 KB · Views: 271
Physics news on Phys.org
e101101 said:
Homework Statement: Part c
Homework Equations: B=Bocos(k•r±⍵t)
E=Eocos(k•r±⍵t)
Irradiance=P/A

I don't know where to start for part (c), I've managed to get (a) and (b).
What is the relationship between irradiance*, I, and the electric field amplitude (by that I mean the electric field amplitude is the E_0 in your E = E_0 \cos(kr \pm \omega t) equation [Note: that equation, as it stands, doesn't apply to this problem. You'll have to modify it a little to apply to this problem])?

In this problem, the irradiance is a function of distance from the light source. What is the relationship between irradiance and distance, in this problem?

Now, based on the above, what is the relationship between the electric field amplitude and distance from the light source?

*(here I'm assuming that "irradiance" is synonymous with "intensity.")

Can someone simply guide me, I think I'm having trouble understanding what the teacher means by just having an x dependance...
Does this mean I only work with the x components of the magnetic field and the electric field? What about the direction fo propagation?
I'm pretty sure it just means that you don't need to worry about forming equations in 3-dimensions for all space. Just concentrate on a single direction (specifically, that direction being the x-axis).

The direction of propagation is the x-axis. So all you need to do is determine E and B as measured along the x-axis.
 
Also, I don't think the problem is asking for the actual directions of the electric and magnetic field vectors. It's assumed that \vec E and \vec B are perpendicular to each other, and both are perpendicular to the direction of wave propagation.

Rather, I think the problem is just asking you to find the magnitudes of E and B, as a function of distance from the light source.
 
collinsmark said:
What is the relationship between irradiance*, I, and the electric field amplitude (by that I mean the electric field amplitude is the E_0 in your E = E_0 \cos(kr \pm \omega t) equation [Note: that equation, as it stands, doesn't apply to this problem. You'll have to modify it a little to apply to this problem])?

In this problem, the irradiance is a function of distance from the light source. What is the relationship between irradiance and distance, in this problem?

Now, based on the above, what is the relationship between the electric field amplitude and distance from the light source?

*(here I'm assuming that "irradiance" is synonymous with "intensity.")I'm pretty sure it just means that you don't need to worry about forming equations in 3-dimensions for all space. Just concentrate on a single direction (specifically, that direction being the x-axis).

The direction of propagation is the x-axis. So all you need to do is determine E and B as measured along the x-axis.

Thank you so much for your reply!
Would I have to consider spherical waves in this problem? Or can I simply treat them as plane waves moving in the x direction (because of the conditions given in the problem).

If I can treat it as a planar wave i would write an equation like:
Ex=Eo(kx±⍵t)

The relationship between irradiance and the amplitudes would be: (1/μ0)(BoEo)
and since Bo=Eo/c
we can rewrite as (1/μ0)(Eo**2)/c
 
e101101 said:
Thank you so much for your reply!
Would I have to consider spherical waves in this problem? Or can I simply treat them as plane waves moving in the x direction (because of the conditions given in the problem).

If I can treat it as a planar wave i would write an equation like:
Ex=Eo(kx±⍵t)

The relationship between irradiance and the amplitudes would be: (1/μ0)(BoEo)
and since Bo=Eo/c
we can rewrite as (1/μ0)(Eo**2)/c
Your final answers will be something sort of like plane waves, but not exactly like plane waves. In other words, modify your

E = E_0 \cos (kr \pm \omega t)
B = B_0 \cos (kr \pm \omega t)

equations such that the (a) amplitude falls off appropriately as a function of distance and (b) instead of using the constants E_0 and B_0 use some other expressions that relate to a 80 W light bulb at 50% efficiency.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
8
Views
1K
Replies
18
Views
2K
Replies
9
Views
742
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
3K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K