EMF Homework Help: Calculating Resultant Force on a Square with Charges Q and q

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Homework Help Overview

The discussion revolves around a problem in electrostatics involving four charges placed at the vertices of a square. The original poster is attempting to determine the conditions under which the net force on one of the charges, Q, is zero, particularly in relation to the other charges, q, positioned at the remaining vertices.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the charges Q and q, questioning the conditions necessary for the resultant force on charge Q to be zero. They discuss the forces acting on Q and the implications of charge signs and distances.

Discussion Status

Some participants have suggested that for the net force on Q to be zero, the charges Q and q must have opposite signs. There is ongoing exploration of the relationships between the forces acting on Q, including repulsive and attractive forces, and how these relate to the distances involved.

Contextual Notes

Participants are considering the geometry of the square, specifically the side length and diagonal, as well as the implications of setting certain forces equal to each other to find relationships between the charges. There is a focus on the assumptions regarding the signs of the charges and the distances between them.

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A charge Q at a vertex of a square and another Q on the opposite corner of the square and other two charges q each of the other vertices. If the force eletrogmanetica on Q is null which the value of Q in terms of q? There is a q such that the resultant force on 4 charges is zero?

My attemp

F = (K.Q.Q)/r^2 + (K.Q.q)/r^2
F = 0
KQ^2 + KQq = 0
Q(KQ + kq) = 0
Q = - q

If q = 0 the resultant force is 0

I correct ?
 
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If the side of the square is r, the length of the diagonal is ...?
At Q three forces are acting. How are they related to get net zero force?
 


rl.bhat said:
If the side of the square is r, the length of the diagonal is ...?
At Q three forces are acting. How are they related to get net zero force?

This is my doubt
 


To get net zero force on Q, Q and q must have opposite sign.
On charge Q, one repulsive force between Q and Q, and two attractive forces between Q and q are acting. What is the distance between Q and Q?
Equate the resultant force of two attractive with the repulsive force to find the relation between Q and q.
 


rl.bhat said:
To get net zero force on Q, Q and q must have opposite sign.
On charge Q, one repulsive force between Q and Q, and two attractive forces between Q and q are acting. What is the distance between Q and Q?
Equate the resultant force of two attractive with the repulsive force to find the relation between Q and q.

Yes I find Q = -q is correct ?
 

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