EMF induced in rotating rod inside uniform magnetic field

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SUMMARY

The discussion focuses on calculating the electromotive force (emf) induced in a 40 cm rotating rod within a uniform magnetic field of 6.4 T at a rotation speed of 15 rad/s. The emf is determined using the formula emf = -B·πr²/T, where r is 20 cm (the radius). The consensus is to use the full period for calculations to find the emf between the center and one end of the rod, while noting that the emf between the two ends of the rod is zero due to equal potential values.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for emf: emf = -ΔΦ/Δt
  • Knowledge of rotational motion and angular velocity (ω = 2π/T)
  • Basic geometry of circles and areas (πr²)
NEXT STEPS
  • Study the principles of Faraday's Law of Electromagnetic Induction
  • Learn about the applications of emf in rotating systems
  • Explore the relationship between angular velocity and induced emf
  • Investigate the effects of varying magnetic field strengths on induced emf
USEFUL FOR

Students studying electromagnetism, physics educators, and engineers working with rotating machinery in magnetic fields.

songoku
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Homework Statement


A 40 cm rod is rotated about its centre inside a region of uniform magnetic field of 6.4 T. Given that the speed of rotation is 15 rad/s, find potential difference between the centre and either end of the rod

Homework Equations


emf = - ΔΦ / Δt

ω = 2π / T

The Attempt at a Solution


emf = - B cos θ . ΔA / Δt = - B . πr2 / T

I just need to plug the numbers with r = 20 cm (because from center to either end of rod)?

Thanks
 
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In one full period T, the radius of the rod which is ##r=20cm## (since ##d=40cm## is the diameter) covers a surface of a full circle which is ##\pi r^2##. You can use the diameter but then you ll have to take the formula ##\pi\frac{d^2}{4}## for the surface of the circle.
 
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Delta2 said:
In one full period T, the radius of the rod which is ##r=20cm## (since ##d=40cm## is the diameter) covers a surface of a full circle which is ##\pi r^2##. You can use the diameter but then you ll have to take the formula ##\pi\frac{d^2}{4}## for the surface of the circle.

For the time, do I use the period because half of the rod travels full circle in one full period or I use half of period because one whole rod covers one full circle in half period?

Thanks
 
songoku said:
For the time, do I use the period because half of the rod travels full circle in one full period or I use half of period because one whole rod covers one full circle in half period?

Thanks
You use the full period for half rod, otherwise if you follow the 2nd approach you find the EMF between the two ends of the rod. But the problem asks for the EMF between one end and the center, that's why we have to take the area that the half rod covers in one full period.
 
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Delta2 said:
You use the full period for half rod, otherwise if you follow the 2nd approach you find the EMF between the two ends of the rod. But the problem asks for the EMF between one end and the center, that's why we have to take the area that the half rod covers in one full period.

If the question asks the emf between two ends of the rod, will the answer be zero because they have the same value and the difference = 0?

Thanks
 
songoku said:
If the question asks the emf between two ends of the rod, will the answer be zero because they have the same value and the difference = 0?

Thanks
Yes, the emf between the two ends is zero.
 
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Thank you very much
 
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