Empirical Formula from Stoichiometry?

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SUMMARY

The discussion focuses on determining the empirical and molecular formulas of adipic acid (CnHmOp) using stoichiometric calculations. A 1.6380g sample of adipic acid combusted to yield 2.960g of CO2 and 1.010g of H2O. The calculations involve converting the masses of CO2 and H2O to moles, followed by determining the moles of carbon, hydrogen, and oxygen in the adipic acid sample. The empirical formula is derived by finding the simplest whole number ratio of these elements.

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Empirical Formula from Stoichiometry!?

Homework Statement


More than 1 billion pounds of adipic acid (MW 146.1 g/mol) is manufactured in the US each year. Most of it is used to make synthetic fabrics. Adipic acid contains only C, H, and O. Combustion of a 1.6380g sample of adipic acid gives 2.960g of CO2 and 1.010 g of H2O. What is the simplest formula for adipic acid? What is its molecular formula?


Homework Equations


(Adipic Acid) + O2 -> CO2 + H2O


The Attempt at a Solution


Convert to .0561 mol H2O
Convert to .0673 mol Co2
Convert to .0112 mol adipic acid using stoichiometry (I understand this part).
 
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Divide each of the moles by the least amount (adipic acid), then you'll get (roughly) even numbers, which is the empirical formula.
 


Use given masses of water and carbon dioxide to calculate masses of hydrogen and carbon in the sample of adipic acid - you will see the sample weighted more. Missing mass is the oxygen. Then calculate moles of H, C and O (not H2, C and O2) and find their ratio as iRaid suggested.
 

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