Energy Absorbed by Ear from 95-dB Sound Wave

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SUMMARY

The discussion centers on calculating the energy absorbed by an eardrum from a 95-dB sound wave. Participants clarify that to find the energy absorbed per second, one must first convert decibels to intensity using the logarithmic formula. The intensity is defined as power divided by area, measured in watts per meter squared. Ultimately, the energy absorbed per second is equivalent to the power received by the eardrum.

PREREQUISITES
  • Understanding of sound intensity and decibel levels
  • Familiarity with logarithmic calculations
  • Knowledge of power and area relationships in physics
  • Basic concepts of energy transfer in sound waves
NEXT STEPS
  • Research the formula for converting decibels to intensity
  • Learn about the relationship between power, area, and intensity in sound waves
  • Explore the effects of sound intensity on human hearing
  • Investigate the physics of sound wave propagation
USEFUL FOR

Students in physics, audio engineers, and anyone interested in the effects of sound on human physiology.

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A 95-dB sound wave strikes an eardrum whose area is 5.0 x 10¯5 m². How much energy is absorbed by the eardrum per second? ...been stuck on this question for so long.
 
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First, convert decibels to "intensity" using that equation with the "log" in it. Intensity equals power divided by area, measured in "watts per meter squared."

Your answer, "energy per second" is the same thing as power.
 
thanks a lot! i get it now =)
 

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