Energy absorbed by the inductor in 4 seconds

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SUMMARY

The discussion focuses on calculating the energy absorbed by an inductor over a period of 4 seconds, utilizing the equations V = L di/dt and Energy = V*I*t. The initial voltage across the inductor is determined to be 6V for the first 2 seconds, leading to an energy calculation of 36 Joules. However, the inclusion of resistance in the calculations is critical, as it accounts for energy dissipation. The final energy absorbed by the inductor, including both stored and dissipated energy, totals 72 Joules.

PREREQUISITES
  • Understanding of inductor behavior in electrical circuits
  • Familiarity with the equations for voltage and energy in inductors
  • Knowledge of integration techniques for calculating energy
  • Basic concepts of resistance in electrical components
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  • Study the general formula for energy stored in an inductor: W = 1/2 L*i^2
  • Learn about the impact of resistance on energy dissipation in inductors
  • Explore integration techniques for calculating energy over time in electrical circuits
  • Investigate the differences between ideal and real inductors in circuit analysis
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Electrical engineering students, circuit designers, and anyone involved in analyzing inductor behavior in electrical systems will benefit from this discussion.

jaus tail
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Homework Statement


upload_2017-12-18_19-35-29.png


Homework Equations


V = L di/dt
Energy = V*I*t

The Attempt at a Solution


First we find out V across L
This V will be there only for 1st 2 seconds as after that there is no change in current.
So V(across L) is L * di/dt = 2 * 6/2 = 6V equation 1
Now Current is a function of time so it's i = 3t equation 2
So to get Energy we use integration.
Energy = integration of V*I*dt where limits are 0 to 2
So now using equation 1 and 2 we get
Energy = integration of 6 * 3t dt from limits 0 to 2
so this is 18 t2/2 t varies from 0 to 2
So this is 9 (4) = 36 which is not in the options.
Where am I wrong.
I even tried other formula of Energy = 1/2 * L * I2 But this gives 24
I'm getting different answer for different formula but neither answer matches options. Where am I wrong?
 

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I don't see where you've taken into account the resistance of the inductor. Sure, the inductor won't be storing the energy lost to heat via the resistance, but it's energy absorbed (and then dissipated) by the inductor nonetheless.

I note that you didn't include the general formula for energy stored in an inductor in your relevant equations. It might prove handy in this instance :wink:
 
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The question is a little ambiguous - but I do think they are looking for total energy, Inductance (stored) and Resistance ( dissipated)
 
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Book says answer is C
But I don't know how they got that. Power in inductor is 1/2 * L * i2
Why do I have to include resistance? The current is given. So current through inductor is known.

W = 1/2 L*i*i
Energy is integrating W*dt as t varies from 0 to time asked in question.
 
jaus tail said:
Why do I have to include resistance?
The inductor, as a real component, has both inductance and resistance due to the resistivity of the coil of wire that it is made from. That wire resistance will dissipate energy in addition to the energy that the inductance will store in its magnetic field.
 
Oh okay. So I'll have to integrate i2R with respect to dt as t varies from 0 to 4 as well. Got it. Thanks.
That gives Energy across L as 36
Energy across R for transient time is 24
Energy across R in steady state is 72
Adding all I get answer as a)
Thanks.
 
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Also -- in this question the current is "set", formally defined -- normally (in a real case) both the inductor and the resistance would be impacting the total current and you would be seeing the impact of both elements more clearly..
 
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