(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2. Relevant equations

Fourier and then V(output) = 4Vs/(n*3.14) * sin (nwt) where Vs is battery here it's 400V

Current = V(output) / X(L). Here X is 2*3.14*100*0.2

3. The attempt at a solution

I got V(output) = 4*400/3.14 = 509.55V This is fundamental Peak output voltage.

So Current peak = 509.55 / impedance. Impedance = 2*3.14*100*0.2 = 125.6 Ohm

So Current peak = 509.55 / 125.6 = 4.06A

But this is not in option.

If i use other method of V = L di/dt

Here for time interval by green line

400 = 0.2 * di/dt

dt = time interval in green part = time period / 4. Frequency = 100 Hz. So Time period = 0.01 seconds

So dt = T/4 = 2.5 milli seconds

So 400 = 0.2 * di / dt

This gives di = 5 A.

But why don't i get correct answer if I go by above method of fourier?

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# Homework Help: Full Bridge Inverter: Got the answer by 1 method, but not by another

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