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Energy, Angular Momentum, Torque, solid ball rolling down loop track? help?

  1. Nov 16, 2012 #1
    Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    A solid brass ball of mass .280g will roll smoothly along a loop-the-loop track when released from rest along the straight section. The circular loop has radius R = 14.0 cm, and the ball has radius r<<R.

    (a) What is h if the ball is on the verge of leaving the track when it reaches the top of the loop? If the ball is released at height h = 6.00R, what are the (b) magnitude and (c) direction of the horizontal force component acting on the ball a point Q?

    Solution and with diagram on first page, #11.8
    www.monmsci.net/~fasano/phys1/Chapter_11_09.pdf

    first what does r<<R mean?? is that the same as r<R?

    a) so the initial E is mgh when the ball is at the very top.
    Ei = Ef
    mgh = 1/2mv^2 + 1/2Iω^2 + mg(2R)

    So what is mg(2R)?? how can we substitute 2R for h? Also where did 2R come from, the problem never mention anything about 2R.

    b) mg(6R) = mg (R) + 1/2mv^2 + 1/2Iω^2

    so i understand that the problem states that h = 6R on the left hand side, but why is the right hand side only R (mgR). What does that R mean?

    thanks!
     
  2. jcsd
  3. Nov 16, 2012 #2

    Simon Bridge

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    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    Yes - but more so.
    It means that the radius of the ball is very much smaller than the radius of the loop - so you are thinking marble on a hoola-hoop sized loop rather than a golf ball on a golf-hole sized loop. (technically a plug is smaller than a plughole right?)
    The ball starts out with an initial height h - then it goes down to the ground, then it goes up to the top of the loop .... how high is the top of the loop from the ground?
    But they did mention an R. What is R?
    You have to read the question - they tell you right at the start.
    BTW: they are actually telling you that h=7R: compare the last two relations again - the RHS has also changed.
     
    Last edited: Nov 16, 2012
  4. Nov 17, 2012 #3
    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    i still dont understand how do we figure out how high is the top of the loop from the ground? The problem mentions "The circular loop track has radius R = 14.0cm" so how do you get 2R? 2R would be 28cm?

    R is the radius of circular loop track. But the problem says R = 14.0cm. Why is it 2R?

    how is it 7R?

    sorry im having a lot trouble with this problem :(
     
  5. Nov 17, 2012 #4

    Simon Bridge

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    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    Well done.
    The loop sits on the ground. R is the distance from the ground to the center ... the ball does not just go from the ground to the center does it? How high is the highest point on the track?
    Like I said - compare with the previous equation.

    To understand this problem you have to remember that gravity does not care which path the ball takes as it goes up and down. All gravity cares about are the vertical distances. If the ball ran down one ramp and up another, it would end up at the same height it started (ignoring air-resistance etc). It does not matter what angle the tracks are.

    In this problem, the ball starts out at some initial height y=y0=h, then it gains kinetic energy by falling (along a track) to the ground (at y=0). The energy it gains doing this is mgh. This is how much energy is available for the rest of the motion.

    The next thing that happens is it enters a loop with a radius of R.
    The loop sits of the floor, so the very top of the loop is a distance y=y1=2R high.

    This is where you get stuck - so I'll stop there for now. Sketch out the apparatus: draw in a ramp that feeds into a loop and draw in the different y positions of everything. Then you'll see it.

    if y0=y1 then the ramp-height is equal to the height of the loop and we can write h=2R.
    What would happen in that case?
     
  6. Nov 17, 2012 #5
    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    i think i get it. i attached a picture.
     

    Attached Files:

  7. Nov 18, 2012 #6

    Simon Bridge

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    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    Good - you've got where the 2R comes in :)
    Drawing stuff is a good idea in physics - even if you are not asked to.

    At this stage - leave the ramp height as h ... this is what you are trying to find right?

    Still aiming to understand the problem, lets explore a bit:
    If h=2R - so the ramp is as high as the top of the loop, what do you think will happen?

    At the bottom of the ramp, the energy is entirely kinetic.
    When the ball goes around the loop - it has circular motion: you will have studied circular motion recently. At the top of the loop, there is a minimum force that has to be in place to keep the ball moving in the same circle.
     
  8. Nov 18, 2012 #7
    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    I think I understand this problem now :)

    So, energy is conserved

    To find h,

    Total energy = KE translational + KE rotational + PE on top of circle

    mgh = 1/2 mv^2 + 1/2Iω^2 + mg(2R)
     
  9. Nov 18, 2012 #8
    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    I think I understand this problem now :)

    So, energy is conserved

    To find h,

    Total energy = KE translational + KE rotational + PE on top of circle

    mgh = 1/2 mv^2 + 1/2Iω^2 + mg(2R)
     
  10. Nov 19, 2012 #9

    Simon Bridge

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    Re: Energy, Angular Momentum, Torque, solid ball rolling down loop track? help!?

    Not bad ... the rotational and tangential speed are related - since the ball is rolling without slipping. But you need to find what that speed has to be.
     
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