Energy conservation with a projectile -

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SUMMARY

The discussion focuses on energy conservation principles applied to a projectile with a mass of 2.0 kg, launched with initial velocity components of 30 m/s in the x-direction and 40 m/s in the y-direction. The kinetic energy (KE) at the highest point of the trajectory is 900 J, despite the y-component of velocity being zero at that instant, as the x-component remains unchanged. The work done in firing the projectile is equal to its initial kinetic energy, confirming that all energy is kinetic at launch.

PREREQUISITES
  • Understanding of basic physics concepts such as kinetic energy (KE) and potential energy (PE)
  • Familiarity with projectile motion and its components
  • Knowledge of work-energy principles, specifically W = KE
  • Ability to apply the Pythagorean theorem to resolve velocity components
NEXT STEPS
  • Study the derivation of kinetic energy formulas, specifically KE = 1/2 mv²
  • Learn about projectile motion equations and how to calculate maximum height
  • Explore the work-energy theorem in greater detail
  • Investigate the effects of air resistance on projectile motion
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of energy conservation in projectile motion.

pinkerpikachu
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Energy conservation with a projectile -- please help!

Homework Statement



A 2.0 kg projectile is fired with initial velocity components Vox= 30 m/n and Voy = 40 m/s from a point on the Earth's surface. Neglect all effects due to air resistance.

A) What is the kinetic energy of the projectile when it reaches the highest point in its trajectory?
B) How much work was done in firing the projectile?

Homework Equations


W=Fx
KE= 1/2mv^2
PE= mgh
W=KE

The Attempt at a Solution



To find the initial velocity, I took the components and did the math as thought it is a right triangle and got 50 m/s. What I don't understand about part A is that when the projectile is at the maximum height, it's only there for an instant and the velocity id zero, which should make the KE zero also correct?

but the answer is apparently 900J

I don't know how to find the highest point of the projectile's path, nor part B

help please?
 
Last edited:
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Are you sure the velocity is zero? Or could that only be the y component of the velocity?
If there is no acceleration velocity does not change. In this example there is no x acceleration.

Using this information gives the correct answer.

Part B, consider that it was fired from rest. The instant it's fired is when it's kinetic energy is maximum. At this point all of its energy is kinetic, use:

[tex]E_k = W[/tex]
 

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