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m84uily
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Homework Statement
The space shuttle is in a 100 km-high circular orbit. It needs to reach a 610 km-high circular orbit to catch the Hubble Space Telescope for repairs. The shuttle's mass is 6.50×104 kg.
How much energy is required to boost it to the new orbit?
Me(mass of earth) = 5.98E24 = 5980000000000000000000000
Re(radius of earth) = 6.37E6 = 6370000
G(gravitational constant) = 6.67E-11 = 0.0000000000667
hi = 100km = 100 000m
hf = 610km = 610 000m
m = 6.5E4 = 65000
Homework Equations
Ugi + Ki = Ugf + Kf
Ug = -Gm1m2/r
K = (1/2)m(v^2)
The Attempt at a Solution
Ugi + Ki = Ugf + Kf
Ugi + Ki = Ugf
Ugi - Ugf = -Ki
-Gm(Me) / (Re + hi) + Gm(Me)/(Re + hf) = -(1/2)m(vi^2)
GmMe = 25926290000000000000
Re + hi = 6470000
Re + hf = 6980000
- 4007154559505.4095826893353941267 + 3714368194842.4068767908309455587 = - (1/2)m(vi^2)
-292786364663.002705898504448568 = - (1/2)m(vi^2)
585572729326.005411797008897136 = m(vi^2)
9008811.2204000832584155214944 = (vi^2)
3001.4681774758304537554833575167
Ki = (1/2)(65000)(3001.4681774758304537554833575167)^2