Conservation of Momentum and/or Energy

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SUMMARY

The discussion focuses on deriving the bullet's speed (v_B) in a ballistic spring system, where a bullet of mass m is fired into a block of mass M, causing the block to compress a spring with spring constant k by a distance d. The conservation of momentum and energy principles are applied, leading to the equations: (m + M)v_f = mv_i for momentum and 1/2mv_i^2 = 1/2k(d)^2 for energy. The challenge lies in correctly linking the final velocity from the momentum equation to the initial velocity in the energy equation.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Familiarity with conservation of energy concepts
  • Knowledge of spring mechanics and Hooke's Law
  • Basic algebra for rearranging equations
NEXT STEPS
  • Study the derivation of the conservation of momentum equation in inelastic collisions
  • Explore the relationship between kinetic energy and potential energy in spring systems
  • Learn about the principles of ballistic pendulum experiments
  • Investigate advanced applications of energy conservation in mechanical systems
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Physics students, educators, and engineers interested in mechanics, specifically those studying dynamics and energy transfer in collision scenarios.

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Homework Statement



You have been asked to design a “ballistic spring system” to measure the speed of bullets. A bullet of mass m is fired into a block of mass M. The block, with the embedded bullet, then slides across a frictionless table and collides with a horizontal spring whose spring constant is k. The opposite end of the spring is anchored to a wall. The spring’s maximum compression d is measured.

Find an expression for the bullet’s speed v_{\rm B} in terms of m, M, k, and d.


Homework Equations



Conservation of momentum m1v1f+m2m2F=m1v1i+m2v2i
Conservation of Energy Ki+Ugi(spring)=Kf+Ugf(spring)


The Attempt at a Solution



Conservation of Momentum rearrangement: (m1+m2)vf=m1v1i

Conservation of energy rearrangement:
1/2mvi^2+0=0+1/2k(delta s)^2
1/2mvi^2=1/2k(delta s)^2
However, I am stuck here. I tried to solve it for vf and got something that is not correct. I know they fit together somehow.
 
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Looks like the Vf of your inelastic momentum conservation, becomes the Vi of your spring energy equation.
 

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