Hello everyone, this is my first post, and I hope I have put this in the right area. I am looking to understand something about the behavior of a low pass filter. When an alternating current is passed through a low pass filter, the higher the frequency, the lower the voltage output of the filter. Therefore, the voltage drop across the resistor must become larger with higher frequencies. Is this because the capacitor becomes less of an interruption in the current flow, with respect to time? That is, because current is flowing more often (probably the wrong word to use), the resistor dissipates more energy? Thanks in advance.(adsbygoogle = window.adsbygoogle || []).push({});

-PWood

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# Energy dissipation in the resistor of a passive lowpass filter

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