- #1
EraXon
< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >
So I know the formula of kinetic energy (mv^2 divided by 2). And I have a mass of 50 kg and a speed of 1 m/s will that mean I online need 25 Joules to make that jump?
So I know the formula of kinetic energy (mv^2 divided by 2). And I have a mass of 50 kg and a speed of 1 m/s will that mean I online need 25 Joules to make that jump?
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