Energy released, capacitor power output

[KMc19]

Homework Statement

a) An electrical device stores energy in a 1.25 x 10^-4 F capacitor at 220 V. How much energy can be stored in this device?

b) If 1.25 J were released from capacitor in 0.25 second, what would be its power output?

I believe I solved (a), but I cannot find out how to go about setting up and solving (b). Please help! :)

Homework Equations

PE=1/2 CV^2

The Attempt at a Solution

a) = 1/2( 1.25 x 10^-4)( 220 V) = 3.025 J


b) I'm not sure about howto set this one up, that's where I'm having problems.

 

[Delphi51]

Power is the rate at which energy is moved or work done.
P = E/t.
You can only do this as an average over the whole 0.25 s, for which the energy is given as 1.25 J.

 

[KMc19]

Thanks Delphi!