Energy Released in Stellar Nucleosynthesis

Click For Summary
SUMMARY

The discussion centers on the calculation of binding energy in stellar nucleosynthesis, specifically during the proton-proton chain reaction. The mass defect formula, ΔM = Z m_p + (A - Z) m_n - m_{nuc}, is utilized to derive binding energy, E_B = ΔM c^2. A participant initially calculated the binding energy as 28.2958 MeV but was corrected to 26.731 MeV due to improper unit handling and misunderstanding of the reaction products. The energy released during nuclear fusion in a main sequence star is thus clarified to be 26.731 MeV.

PREREQUISITES
  • Understanding of mass defect and binding energy concepts
  • Familiarity with nuclear reaction equations
  • Basic knowledge of units in physics, particularly MeV and MeV/c²
  • Calculus-based physics background, particularly in electromagnetism
NEXT STEPS
  • Study the proton-proton chain reaction in detail
  • Learn about the role of binding energy in nuclear fusion
  • Explore the differences between mass-energy equivalence and energy units
  • Investigate other fusion processes in stars, such as the CNO cycle
USEFUL FOR

Astronomy students, astrophysicists, and anyone interested in understanding nuclear fusion processes in stars will benefit from this discussion.

Amrator
Messages
246
Reaction score
83
This is taken from page 226 in Essential Astrophysics by Lang:

"The mass defect, ##ΔM##, for a nucleus containing ##A## nucleons, ##Z## protons, and ##A-Z## neutrons is
$$ΔM = Z m_p + (A - Z) m_n - m_{nuc}$$ where ##A## is the mass number of the nucleus, ##Z## is the atomic number, ##m_p## is the mass of the proton, ##m_n## is the mass of the neutron, and ##m_{nuc}## is the mass of the nucleus.

The binding energy, ##E_B##, used to assemble the nucleus from its constituent nucleons is:
$$E_B = ΔM c^2$$ The binding energy measures how tightly bound a nucleus is."

So mass defect represents both the difference between the mass of a composite particle and the sum of the masses of its parts and the binding energy released during nuclear fusion? If I wanted to calculate the binding energy released during the proton-proton chain reaction, would I simply plug in 938.272 MeV for ##m_p##, 939.5654 MeV for ##m_n##, 2 for ##Z##, 2 for ##A-Z## (4 total nucleons minus 2 protons for a helium atom), and 3727.379 MeV for ##m_{nuc}##? This gives me 28.2958 MeV. Multiplying that by (3 x 10^8 m/s)^2 gives me 2.54662 x 10^18. Is this correct? Is that the energy released during a nuclear fusion reaction in a main sequence star?

If it helps to know, I took both calculus-based E&M (level of Purcell) and multi-variable calculus/vector calculus last semester. I have not taken university-level chemistry yet.

Thanks, guys!
 
Astronomy news on Phys.org
Amrator said:
This gives me 28.2958 MeV. Multiplying that by (3 x 10^8 m/s)^2 gives me 2.54662 x 10^18. Is this correct? Is that the energy released during a nuclear fusion reaction in a main sequence star?
The first part is (roughly that many MeV), but you shouldn't multiply that by c^2 - MeV is already a unit of energy. I.e., the values you used are not in MeV, but in the convenient mass units of MeV/c^2. If you multiply a mass of 1 MeV/c^2 by c^2 you get 1 MeV of energy.

(Or you can just forget about mass altogether and use units of energy from start to finish)
 
  • Like
Likes   Reactions: D H
Amrator said:
This gives me 28.2958 MeV. ... Is that the energy released during a nuclear fusion reaction in a main sequence star?
@Bandersnatch already caught your big error, what was not using units correctly. The answer to the highlighted question is no. Some of that binding energy represents two protons becoming two neutrons. An easy way to get the correct answer is to look at what the system starts and ends with. The proton-proton chain changes four protons and two electrons into an alpha particle. Add the numbers up and you get 26.731 MeV rather than 28.2958 MeV.
 
  • Like
Likes   Reactions: Bandersnatch

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
13
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K