Comparing Spring Compression in Two Trials with Different Release Heights

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SUMMARY

The forum discussion centers on a physics experiment comparing the compression of springs in two trials involving a 1.5 kg block. In Trial 1, the block slides down a frictionless ramp and collides with an uncompressed spring, while in Trial 2, the block is dropped from the same height onto an identical spring. The key equations used are gravitational potential energy (Eg = mgh) and elastic potential energy (Esp = 1/2kx²). The conclusion drawn is that the height (h) for both trials is the same, leading to the same maximum compression of the springs.

PREREQUISITES
  • Understanding of gravitational potential energy (Eg = mgh)
  • Knowledge of elastic potential energy (Esp = 1/2kx²)
  • Familiarity with the concept of energy conservation
  • Basic principles of spring mechanics
NEXT STEPS
  • Explore the concept of energy conservation in mechanical systems
  • Study the behavior of springs under varying conditions
  • Learn about the effects of friction on energy transfer in physical experiments
  • Investigate the relationship between spring constant (k) and compression
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of energy conservation and spring mechanics in experimental settings.

phzzo
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Homework Statement


IMG_20150511_240522_446.jpg

Students in a physics class set up an experiment to examine the behavior of springs being compressed under various conditions. In the first trial of the experiment, students released a 1.5 kg block from rest at the top of a ramp. The block slid down the ramp, across a horizontal surface, and then collided with an uncompressed, massless spring. Students attached a marker to the spring so they could see how far it was compressed in bringing the block to rest. All surfaces in trial 1 were effectively frictionless.
In trial 2, the block was dropped from the same height directly above an identical spring. This spring was placed such that its bottom had the same height as the spring in trial 1 (as shown in the diagram). Again the students recorded the maximum compression of the spring in bringing the block to rest. Indicate which of the two springs experienced a greater compression in bringing the block to rest.

Homework Equations


Eg = mgh
Esp = 1/2kx2

The Attempt at a Solution


Each block will have a potential energy that is conserved as elastic energy. The blocks have the same mass and the springs have the same k. For each block and spring, mgh = 1/2kx2, but I'm not sure about the h for Trial 2. Would it be the same as Trial 1?
 
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phzzo said:
I'm not sure about the h for Trial 2. Would it be the same as Trial 1?

Try assuming that in both cases the spring is compressed some amount (say 50%?) after the collision. Draw that and work out the height that you would use to calculate the PE that has been converted into energy stored in the spring. Can they be the same?
 

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