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Energy stored and # turns in an MRI machine (solenoid)

  1. Apr 10, 2010 #1
    1. MRI (magnetic resonance imaging) is a medical technique that produces detailed "pictures" of the interior of the body. The patient is placed into a solenoid that is 40 cm in diameter and 1.0 m long. A 100 A current creates a 5.0 T magnetic field inside the solenoid. To carry such a large current, the solenoid wires are cooled with liquid helium until they become superconducting (no electric resistance).

    2.U = 0.5LI2
    N = l/d

    3. L = flux/I = AB/I = 0.00628H
    U = 0.5LI2 = 31.4H

    N = l/d = 2.5 turns

    Am I getting this right?
  2. jcsd
  3. Apr 10, 2010 #2
    Is this correct?
  4. Apr 10, 2010 #3
    Ok, I now know that 31.4H is incorrect. Can someone explain what I'm doing wrong?
  5. Apr 11, 2010 #4
    Any suggestions?
  6. Apr 11, 2010 #5


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    I see no way to get an exact answer from the information you have provided but you can get close. You can calculate the energy stored in the magnetic field, if you make assumptions about the field (e.g., the field is uniform throughout the solenoid). Your inductance formula then gives the number of turns.
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