Energy Stored in a Charged Capacitor

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A 12.0-V battery charges a capacitor with 54.0 μC, prompting a calculation of the stored energy. The formula used is 1/2CV^2, but the user initially calculates 3.88 x 10^-4 J, while the book states 3.24 x 10^-4 J. Suggestions include using the charge and voltage in the formula 1/2QV to verify results. The user remains uncertain about their calculations and seeks clarification on the discrepancy. The discussion emphasizes the importance of correctly applying formulas to determine energy stored in capacitors.
shadyy
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Homework Statement



A 12.0-V battery is connected to a capacitor, resulting in 54.0 μC of charge stored on the capacitor. How much energy is stored in the capacitor?


Homework Equations



1/2CV^2

The Attempt at a Solution



At first this problem looks to be easy for me but somehow I get a complete different answer than the back of the book.

I plugged in all the variables and solved and got 3.88 x 10^-4 J

1/2(5.4x10^-6)(12)^2

The answer I get in the back of the book is 3.24 x 10^-4 J

Can someone please explain to me what I am doing wrong?
 
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shadyy said:

Homework Statement



A 12.0-V battery is connected to a capacitor, resulting in 54.0 μC of charge stored on the capacitor. How much energy is stored in the capacitor?


Homework Equations



1/2CV^2

The Attempt at a Solution



At first this problem looks to be easy for me but somehow I get a complete different answer than the back of the book.

I plugged in all the variables and solved and got 3.88 x 10^-6 J

1/2(5.4x10^-6)(12)^2

The answer I get in the back of the book is 3.24 x 10^-4 J

Can someone please explain to me what I am doing wrong?

Try finding Q first using C=Q/V, then try 1/2QV. This will either confirm that you are right and the book is wong, or that the book is right and that you are wrong.
 
Thanks for the quick reply. I tried that and I got a completely different answer. I don't think the book is wrong. I think I'm doing something wrong. I'll try to figure it out I guess.
 
Energy stored = 0.5QV
You know Q (charge) and you know V
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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