Energy to put space shuttle in orbit

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SUMMARY

The energy required to place the space shuttle into orbit at an altitude of 300 km is calculated using gravitational potential energy and kinetic energy equations. The mass of the space shuttle is 6.8 x 104 kg, and the mass of the Earth is 6.0 x 1024 kg. The correct total energy needed is 2.2 x 1012 J, which accounts for the difference between kinetic energy (4.2 x 1012 J) and potential energy (2.1 x 1012 J). The calculations must consider the change in height from the Earth's surface to the orbiting altitude.

PREREQUISITES
  • Understanding of gravitational potential energy (GPE) and kinetic energy (KE) equations
  • Familiarity with the universal gravitational constant (G = 6.67 x 10-11 N m2/kg2)
  • Knowledge of mass and radius of Earth (mass = 6.0 x 1024 kg, radius = 6.4 x 106 m)
  • Basic principles of orbital mechanics
NEXT STEPS
  • Study the derivation of gravitational potential energy equations
  • Learn about the concept of total mechanical energy in orbital motion
  • Explore the differences between kinetic and potential energy in space applications
  • Investigate the principles of launching spacecraft and achieving orbit
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in the mechanics of space travel and orbital dynamics will benefit from this discussion.

calculator20
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Homework Statement


The space shuttle orbits about 300km above the surface of the Earth. The shape of the orbit is circular and the mass of the space shuttle is 6.8*104kg. The mass of the Earth is 6.0*1024kg and the radius of the Earth is 6.4 *106m. Calculate the energy needed to put the space shuttle into orbit.


Homework Equations



KE=GMm/rp

The Attempt at a Solution


Using G=6.67*10-11 with the mass of the Earth and shuttle and the radius of the Earth gives 4.2*1012J but the answer should be 2.2*1012J according to the book. Where am I going wrong?
 
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Think about what the gravitational potential energy GMm/r means.

The shuttle lifts (or rises) from re to re+300 km, where re is the radius of the earth.
 
oops!

Hi calculator20! :smile:
calculator20 said:
The space shuttle orbits about 300km above the surface of the Earth. The shape of the orbit is circular and the mass of the space shuttle is 6.8*104kg. The mass of the Earth is 6.0*1024kg and the radius of the Earth is 6.4 *106m. Calculate the energy needed to put the space shuttle into orbit.

KE=GMm/rp

erm :redface: … you can't just leave it there :rolleyes: … it'll crash! :eek:

try giving it a shove! :smile:
 
If I do GMm/re I get 4.2*10 to the 12, GMm/re + 300000 gives 4.06 * 10 to the 12. The difference between them isn't 2.2 *10 to the 12?
I get
 
i am having exactly the same difficulty, its frustrating the hell out of me.
either i am not seeing something or there is an error in the answer page
 
yesyesyes said:
i am having exactly the same difficulty, its frustrating the hell out of me.
either i am not seeing something or there is an error in the answer page

Welcome to PF.

They want the total energy.

What is total energy to move from the surface of Terra to a 300km height?

What must the object have to be in orbit?

Etotal = ΔKE + ΔPE
 
so basically 2.2= KE (4.2) - PE (2.1)
allowing for roundings
?

Thanks a lot x
 

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