Energy to separate charge +e and -e

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SUMMARY

The energy required to separate an electric charge +e and a charge -e from an initial separation distance d to infinity is derived using the formula W = e² / (4π * ε₀ * d). The force between the charges is calculated using Coulomb's law, F = (q1*q2)/(4π * ε₀ * d²), where q1 = +e and q2 = -e. The integration of this force over the distance from d to infinity confirms the expression for work done, which aligns with the potential energy change formula, W = ΔU.

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Homework Statement


Derive an expression for the energy required to separate to infinity an electric charge +e and a charge -e, their initial separation being d.

Homework Equations



F = (q1*q2)/(4∏ * ε0 * d2)

The Attempt at a Solution


Basically what I've done is first make q1= +e and q2= -e and substituted them into the equation above. I then integrated this equation as show below...

Work done = d F = d -e2 / (4∏ * ε0 * d2)

After integrating this with respect to d, I get the answer...

W = e2 / (4∏ * ε0 * d)

Is this correct or did i make it all up in my head, thanks for any replies :)
 
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I think this is correct. The potential of a charge, v = kq/r , is found this way, i.e. by integrating from d to infinity of a test charge and then dividing by the charge.
 
An easier way to do this is to work out the change in potential energy.
W = ΔU
 

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