Electric Field due to multiple point charges

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SUMMARY

The discussion focuses on deriving the electric field at point P due to two positive point charges, Q1 and Q2, located at distances h and √2 h, respectively. The electric field equations used are E1 = k Q1/h² and E2 = k Q2/2h², with components calculated separately for each charge. Participants confirm that both vector component notation and magnitude-angle notation are acceptable for expressing the resultant electric field, depending on the problem's requirements. Sketching the vectors is recommended for clarity in determining directions and angles.

PREREQUISITES
  • Understanding of electric field concepts and equations, specifically E = k q/r²
  • Knowledge of vector decomposition into components
  • Familiarity with trigonometric functions, particularly cosine and sine for angles
  • Ability to sketch vector diagrams for visual representation of forces
NEXT STEPS
  • Learn about vector addition in physics to combine electric field vectors
  • Study the principles of superposition in electric fields
  • Explore the concept of electric potential and its relation to electric fields
  • Investigate the effects of multiple point charges on electric fields in different configurations
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields generated by multiple point charges.

tarkin
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Homework Statement



[/B]
Derive expressions for the magnitude and direction of the electric field at point P and the potential
at R.

Charges Q1 and Q2 are both positive.
pointcharges.jpg


Distance from Q1 to P is h, distance from Q2 to P is √2 h

Homework Equations



E = k q/r^2

The Attempt at a Solution



I started with finding E field at point P for each of the 2 charges, giving:

E1 = k Q1/h^2

E2 = k Q2/2h^2

Then separate into x and y components.
For E1, the x component is 0, and the y component is just the total E1.
For E2, the x component is E2 * cos45 , and the y component is E2 * sin45. (I think.)

Is it okay to give the answer as just (magnitude) x direction + (magnitude) y direction ?

Or should the answer be given as just 1 number for magnitude, and one angle for direction? Wouldn't this give some horrible expression?
 
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tarkin said:

Homework Statement



[/B]
Derive expressions for the magnitude and direction of the electric field at point P and the potential
at R.

Charges Q1 and Q2 are both positive.View attachment 112977

Distance from Q1 to P is h, distance from Q2 to P is √2 h

Homework Equations



E = k q/r^2

The Attempt at a Solution



I started with finding E field at point P for each of the 2 charges, giving:

E1 = k Q1/h^2

E2 = k Q2/2h^2

Then separate into x and y components.
For E1, the x component is 0, and the y component is just the total E1.
For E2, the x component is E2 * cos45 , and the y component is E2 * sin45. (I think.)
You should sketch in the vectors on the figure so that you can get an idea of the directions of the components. No doubt there's angles of 45° involved, but a sketch will help you to locate where those angles sit.
Is it okay to give the answer as just (magnitude) x direction + (magnitude) y direction ?

Or should the answer be given as just 1 number for magnitude, and one angle for direction? Wouldn't this give some horrible expression?
If the question doesn't specify a preferred method then either format for a vector should be acceptable. You might find that the expression for the angle simplifies a good amount through cancellation of variables.
 
gneill said:
You should sketch in the vectors on the figure so that you can get an idea of the directions of the components. No doubt there's angles of 45° involved, but a sketch will help you to locate where those angles sit.

If the question doesn't specify a preferred method then either format for a vector should be acceptable. You might find that the expression for the angle simplifies a good amount through cancellation of variables.

Okay, thank you!
 

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