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Energy Transformation equation for a free fall

  1. Oct 25, 2006 #1
    One of the discussion questions in a lab I did which was basically a free falling object where the kinetic and potential energies were measured. It asks what is the energy transformation equation for a free fall (1-step transformation).
    Is it just:
    Total Energy = Potential gravitational energy + Kinetic energy
    Et= mgh + mv2/2

    Then just cancel out the mass or am I going in the total wrong direction with this?
     
  2. jcsd
  3. Oct 25, 2006 #2

    radou

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    Homework Helper

    Total energy is conserved, which means that mgh + 1/2 mv^2 = C, where C is a constant. Use the equations for h(t) and v(t) for a free fall and plug them into the energy equation to convince yourself that energy is constant for every moment t.
     
    Last edited: Oct 25, 2006
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