Energy Transformation equation for a free fall

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SUMMARY

The energy transformation equation for a free-falling object is defined as Total Energy = Potential Gravitational Energy + Kinetic Energy, represented mathematically as Et = mgh + 1/2 mv². In this equation, total energy is conserved, meaning that mgh + 1/2 mv² equals a constant (C). To validate this conservation of energy, one can substitute the equations for height h(t) and velocity v(t) during free fall into the energy equation, demonstrating that energy remains constant at any moment t.

PREREQUISITES
  • Understanding of gravitational potential energy (mgh)
  • Familiarity with kinetic energy (1/2 mv²)
  • Basic knowledge of free fall motion equations (h(t) and v(t))
  • Concept of conservation of energy in physics
NEXT STEPS
  • Study the derivation of the equations for free fall motion (h(t) and v(t))
  • Explore the implications of energy conservation in different physical systems
  • Learn about energy transformation in other contexts, such as projectile motion
  • Investigate real-world applications of energy conservation principles in engineering
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding energy transformations in free fall scenarios.

jman1114
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One of the discussion questions in a lab I did which was basically a free falling object where the kinetic and potential energies were measured. It asks what is the energy transformation equation for a free fall (1-step transformation).
Is it just:
Total Energy = Potential gravitational energy + Kinetic energy
Et= mgh + mv2/2

Then just cancel out the mass or am I going in the total wrong direction with this?
 
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Total energy is conserved, which means that mgh + 1/2 mv^2 = C, where C is a constant. Use the equations for h(t) and v(t) for a free fall and plug them into the energy equation to convince yourself that energy is constant for every moment t.
 
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