MHB Engineering Mechanics: depth of crater

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The depth of the Taal volcano's crater was calculated based on a scenario involving a helicopter dropping a bomb from 20 meters above the surface. The bomb's fall time can be determined using the equation of motion, while the sound's travel time to the helicopter is calculated using the speed of sound. The total time from the bomb release to the sound reaching the helicopter is 9 seconds. By setting up equations for both the bomb's fall and the sound's travel, the depth of the crater can be accurately determined. This approach combines kinematic equations with sound propagation principles to solve the problem effectively.
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The depth of the crater of the Taal volcano was calculated in the following manner: From a helicopter flying vertically upward at 6m/s. A small bomb was released at the instant the helicopter was 20m above the crater surface. The sound of explosion was heard 9sec later. If the speed of sound is 335m/s, what is the depth of the crater?
 
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I would begin by writing a function that expresses the helicopter's height (in meters) above the surface as a function of time (measured in seconds), where \(t=0\) corresponds to the instant the bomb was dropped.

Then, please answer these questions:
  • If \(d\) is the depth of the crater, how far did the bomb fall and how long would it take to fall that distance (presumably ignoring drag)?
  • How long would it take for the sound of the explosion to reach the rising helicopter?
 
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