Engineering Practice Problem for a Pin-Connected Frame

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To solve the engineering practice problem for a pin-connected frame, it is recommended to treat the structure as two separate entities due to the central pin. Participants emphasize the importance of creating Free Body Diagrams (FBDs) to visualize forces acting on each section. The discussion highlights the need to apply 2D equilibrium equations, specifically focusing on force and moment calculations. Clarifications on assumptions regarding force equilibrium are encouraged to ensure accuracy in solving the problem. Properly documenting the work is essential for receiving further assistance.
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Homework Statement
Stuck on solving this practice problem for the pin connected frame
Relevant Equations
2D Equilibrium, Fx, Fy, M
1651165244951.png

Have identified what i need to find, but not sure how to proceed since there is a pin in the centre, do I treat it as two separate structures?
 
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engineerintraining said:
Homework Statement:: Stuck on solving this practice problem for the pin connected frame
Relevant Equations:: 2D Equilibrium, Fx, Fy, M

View attachment 300720
Have identified what i need to find, but not sure how to proceed since there is a pin in the centre, do I treat it as two separate structures?
Welcome to PF.

Per the PF Rules, you need to show your work before we can help. So yes, start by treating it as two separate structures and show the FBDs please. Thank you.
 
1651166148374.png

this is what I have, then based on this i was thinking that i could assume this:
1651166198165.png

Does that look right?
 
Sure. That is the force equilibrium for the right part. What else can you deduce?
 
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Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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