- #1

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## Homework Statement

http://i.imgur.com/VFb5rwj.png

## Homework Equations

## The Attempt at a Solution

First, I drew the FBD for the system, one horizontal force at A, one force perpendicular to the beam at B, and the weight.

Writing out the equilibrium equations:

The sum of forces in the y direction should be 0, so I have the equation:

Nb cos(θ) - W = 0, which can be rearranged for Nb later on.

Then I took the moment about point A:

Nb (a/cosθ) - Wcosθ (L/2) = 0

Eventually, it simplifies out to cos^-1 ( (2a/L) ^(1/3) ) = θ

I don't think I got the right answer, but can someone help me identify my error? Thank you in advance.