# Engineering Statics Equilibrium System Question

## Homework Statement

http://i.imgur.com/VFb5rwj.png

## The Attempt at a Solution

First, I drew the FBD for the system, one horizontal force at A, one force perpendicular to the beam at B, and the weight.
Writing out the equilibrium equations:
The sum of forces in the y direction should be 0, so I have the equation:
Nb cos(θ) - W = 0, which can be rearranged for Nb later on.
Then I took the moment about point A:
Nb (a/cosθ) - Wcosθ (L/2) = 0
Eventually, it simplifies out to cos^-1 ( (2a/L) ^(1/3) ) = θ

I don't think I got the right answer, but can someone help me identify my error? Thank you in advance.

Why do you think you have the wrong answer?

IDK, it looks just so completely wrong. and also it says that describe it in terms of w, a, and l and I have no w.

Would changing W also change θ?

Also your answer is consistent with the units. If W was in the solution then the units would get screwed up.

1 person
Hmm, I suppose you're right, thank you for the replies.