Engineering Statics Equilibrium System Question

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Homework Statement


http://i.imgur.com/VFb5rwj.png


Homework Equations





The Attempt at a Solution


First, I drew the FBD for the system, one horizontal force at A, one force perpendicular to the beam at B, and the weight.
Writing out the equilibrium equations:
The sum of forces in the y direction should be 0, so I have the equation:
Nb cos(θ) - W = 0, which can be rearranged for Nb later on.
Then I took the moment about point A:
Nb (a/cosθ) - Wcosθ (L/2) = 0
Eventually, it simplifies out to cos^-1 ( (2a/L) ^(1/3) ) = θ

I don't think I got the right answer, but can someone help me identify my error? Thank you in advance.
 

Answers and Replies

  • #2
907
88
Why do you think you have the wrong answer?
 
  • #3
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IDK, it looks just so completely wrong. and also it says that describe it in terms of w, a, and l and I have no w.
 
  • #4
907
88
Would changing W also change θ?

Also your answer is consistent with the units. If W was in the solution then the units would get screwed up.
 
  • #5
79
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Hmm, I suppose you're right, thank you for the replies.
 

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