Enthelpy change of a neutralisation reaction

[IDK10]

Homework Statement

Given the reaction K₂CO₃(s) + 2HCl(aq) → 2KCl(aq) + CO₂(g) + H₂O(l), I need to find the enthalpy change in J, given that:
The specific heat capacity of water is 4.2J g^-1 °C^-1, and
The mass change of potassium carbonate is 2.98g, and the temperature change was °6C, and the volume of acid used was 30cm³.

Homework Equations

ΔH = -qmΔT
number of moles of acid neutralised = number of moles of water formed

The Attempt at a Solution

Considering it is a neutralisation reaction, I did the ΔH = -qmΔT equation. So, -4.2x-2xm=x
x/(2x0.03)
But what do I use for m?

 

[mjc123]

What undergoes a temperature change of 6°C?

 

[IDK10]

What undergoes a temperature change of 6°C?

Exothermic

We only do neutralisation, combustion and formation enthalpy changes.

 

[Borek]

Exothermic

We only do neutralisation, combustion and formation enthalpy changes.

I am afraid you have not understood nor answered the mjc's question, which points you in the right direction.

You can't blindly apply any formula without knowing what it describes.