Enthelpy change - Using tables to find specific heat

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The discussion revolves around calculating the change in enthalpy of argon when cooled from 100 to 25 °C using the equation Δh = cp ΔT. The specific heat value used is from a table that lists ideal-gas specific heats at 300 K, which raises questions about its applicability to the given temperature range. Participants express confusion over why a specific heat value at 300 K is used when the temperatures in the problem are significantly different. It is suggested that the textbook simplifies the process by using a standardized cp value for convenience, despite potential inaccuracies. The consensus indicates that using a single cp value is a practical approach for educational purposes, even if it may not reflect precise conditions.
JJBladester
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Homework Statement



Calculate the change in the enthalpy of argon, in KJ/kg, when it is cooled from 100 to 25 °C.

Homework Equations



\Delta h = c_{p} \Delta T

Where \Delta h is the change in enthalpy, c_{p} is the specific heat, and \Delta T is the change in temperature.

The Attempt at a Solution



\Delta h = c_{p,avg} \Delta T

\Delta h_{argon} = c_{p,avg} \Delta T=\left (.5203\frac{kJ}{kg\cdot C} \right )\left (100 C-25C \right )=39.0\frac{kJ}{kg}

My book has a table at the back that is labeled Ideal-gas specific heats of various common gases at 300 K. The answer given to this question uses the cp values listed in this table. This makes no sense to me as c_{p,avg} would be (cp at T1 + cp at T2)/2.

How can the book use the values from a table where cp values are given for temperature at 300 K?
 
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How can the book use the values from a table where cp values are given for temperature at 300 K?

Are you asking why they would use the cp value for 300K for the solution? That'd be just cause they're lazy and don't actually expect you to know what the specific heat at 373K and at 298K is.

Or are you asking how they can generate a cp average value at 300K in the first place? They'd do that by conducting experiments to generate cp values at 300K and averaging those out.
 
Coushander said:
Are you asking why they would use the cp value for 300K for the solution? That'd be just cause they're lazy and don't actually expect you to know what the specific heat at 373K and at 298K is...

Yes, I'm asking why the solution to this problem is for cp at a temperature completely unrelated to the temperatures in the problem. Is it that the average of the temperatures (336K) can be reasonably approximated to be 300K with little error?
 
JJBladester said:
Yes, I'm asking why the solution to this problem is for cp at a temperature completely unrelated to the temperatures in the problem. Is it that the average of the temperatures (336K) can be reasonably approximated to be 300K with little error?

I'm assuming that it's a textbook. As I said, it's likely for the sake of convenience on the part of the publisher, because it wouldn't be realistic to publish a huge list of specific heats for every molecule at different temperatures. The list would be astronomical. It's easier and cheaper for them to standardize only one value for the molecule and then write their textbook questions in a range where that standard is reasonably applicable.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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