1. The problem statement, all variables and given/known data A current of 10A is maintained for 1s in a resistor of 25Ω while the temperature of the resistor is kept constant at 27°C. This resistor is thermally insulated with a mass of 10g. If it has a specific heat of 836 J/kg*K. What is the entropy change of the resistor? Universe? 2. Relevant equations 3. The attempt at a solution Ok so if the wire is thermally insulated at a constant temperature of 27°C, Q=0 therefore W=0 because it is isothermal and adiabatic So if entropy is TdS= dU - dW so ΔS = 0J/K? However this is wrong...the answer is 5.78J/K and im confused at to how they got this... any suggestions?