Entropy of water and reservoir

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SUMMARY

The discussion focuses on calculating the change in entropy for 1 kg of water heated from 0 degrees Celsius to 100 degrees Celsius when in contact with a heat reservoir at 100 degrees Celsius. The entropy change for the water is calculated using the formula ΔSw = mcln(Tf/Ti), where m is the mass, c is the specific heat capacity (4186 J/K), Tf is the final temperature, and Ti is the initial temperature. For the heat reservoir, the change in entropy is determined using ΔS = ΔQ/T, considering the heat flow into and out of the reservoir. The signs of heat flow must be carefully tracked to ensure accurate calculations.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically entropy.
  • Familiarity with the formula for entropy change: ΔS = ΔQ/T.
  • Knowledge of specific heat capacity, particularly for water (4186 J/K).
  • Basic algebra for manipulating logarithmic equations.
NEXT STEPS
  • Research the concept of heat reservoirs and their properties in thermodynamic systems.
  • Learn about the implications of infinite heat capacity in thermal equilibrium scenarios.
  • Study the derivation and applications of the entropy change formula in different contexts.
  • Explore examples of entropy calculations in various thermodynamic processes.
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone interested in understanding heat transfer and entropy changes in thermal systems.

Slepton
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Homework Statement



1 Kg of water is heated at 0 degree C is brought into contact with a large heat reservoir at 100 degrees C. When the water has reached 100 degrees C, what has been the change in entropy of the water? And of the heat reservoir ? what has been the change in the entire system consisting of both water and the heat reservoir?


Homework Equations



\DeltaSw = mcln(Tf/Ti)

where
m = mass of water
c = specific heat capacity of water ( 4186 J/K)
Tf = final common temperature of water and the reservoir
Ti = initial temperature of water (and also reservoir for part b of the question)



The Attempt at a Solution


The application of formula above gave me answer for entropy change in water but not for reservoir and the whole system. Some help anticipated.
 
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Slepton said:

Homework Statement



1 Kg of water is heated at 0 degree C is brought into contact with a large heat reservoir at 100 degrees C. When the water has reached 100 degrees C, what has been the change in entropy of the water? And of the heat reservoir ? what has been the change in the entire system consisting of both water and the heat reservoir?


Homework Equations



\DeltaSw = mcln(Tf/Ti)

where
m = mass of water
c = specific heat capacity of water ( 4186 J/K)
Tf = final common temperature of water and the reservoir
Ti = initial temperature of water (and also reservoir for part b of the question)



The Attempt at a Solution


The application of formula above gave me answer for entropy change in water but not for reservoir and the whole system. Some help anticipated.

You are assuming that the reservoir has an infiinite heat capacity such that any amount of loss or addition of heat will have no (an infinitessimal) change in temperature. So you cannot use this formula.

To determine the change in entropy of the reservoir just use the definition of entropy:

\Delta S = \Delta Q/T

Since T does not change, this is simply a matter of looking at the heat flow to/from the reservoir. Be careful about the signs: - is heat flow out; + is heat flow into the reservoir.

AM
 
consider the heat flow of the system. Negative of heat gained by 1 kg of water is the heat lost by the reservoir. From that calculate the change in entropy. Keep track of the signs.

Good luck
 

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